Let us first define Hypotenuse Leg (HL) congruence theorem:
<em>If the hypotenuse and one leg of a right angle are congruent to the hypotenuse and one leg of the another triangle, then the triangles are congruent.</em>
Given ACB and DFE are right triangles.
To prove ΔACB ≅ ΔDFE:
In ΔACB and ΔDFE,
AC ≅ DF (one side)
∠ACB ≅ ∠DFE (right angles)
AB ≅ DE (hypotenuse)
∴ ΔACB ≅ ΔDFE by HL theorem.
Answer:
Step-by-step explanation:
5(t+3)=-3.5
distribute
5t+15=-3.5
subtract 15 from both sides
5t= -18.5
divide both sides by 5
t=-3.7
Answer:
y =8
Step-by-step explanation:
1/2y+2/5=4 2/5
Subtract 2/5 from each side
1/2y+2/5-2/5=4 2/5-2/5
1/2 y = 4
Multiply each side by 2
1/2y *2 = 4*2
y = 8
51 and the other one us 15 your welcome
Answer:
I think 60
Step-by-step explanation:
have a great day
