Answer:
If (K + 1)^2 = 2n + (n^2)/2, then the answer is Yes, else No.
Step-by-step explanation:
Sum of first K + 1 odd numbers (S): 1 + 3 + 5 + ... + (2K - 3) + (2K - 1) + (2K + 1).
(1 + 3 + 5 + ... + (2K - 3) + (2K - 1) + (2K + 1)) + ((2K + 1) + (2K - 1) + (2K - 3) + ... + 5 + 3 + 1 ) = (2K + 2) + (2K + 2) + (2K + 2) + ... + (2K + 2) + (2K + 2) + (2K + 2) (repeat K + 1 times) = (2K + 2)(K + 1) = 2S
2S = (2K + 2)(K + 1)
S = (2K + 2)(K + 1)/2
S = (2K^2 + 4K + 2)/2
S = K^2 + 2K + 1
S = (K + 1)^2
(4n + n^2)/2 = 2n + (n^2)/2
3m + 12 < 24
3m + 12 - 12 < 24 - 12
3m < 12
3/3m < 12/3
m < 4
Twenty seven minus ten plus four
Answer:
20x - 6
Step-by-step explanation:
You just multiply 2 by 10x and by -3
Answer:
Step-by-step explanation:
the answer is 2
