Answer: (0.076, 0.140)
Step-by-step explanation:
Confidence interval for population proportion (p) is given by :-
![\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%5Cpm%20z_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
, where
= sample proportion.
n= sample size.
= significance level .
= critical z-value (Two tailed)
As per given , we have
sample size : n= 500
The number of Independents.: x= 54
Sample proportion of Independents![\hat{p}=\dfrac{x}{n}=\dfrac{54}{500}=0.108](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%5Cdfrac%7Bx%7D%7Bn%7D%3D%5Cdfrac%7B54%7D%7B500%7D%3D0.108)
Significance level 98% confidence level :
By using z-table , Critical value :
The 98% confidence interval for the true percentage of Independents among Haywards 50,000 registered voters will be :-
![0.108\pm (2.33)\sqrt{\dfrac{0.108(1-0.108)}{500}}\\\\=0.108\pm2.33\times0.013880634\\\\=0.108\pm0.03234187722\\\\\approx0.108\pm0.032=(0.108-0.032,\ 0.108+0.032)=(0.076,\ 0.140)](https://tex.z-dn.net/?f=0.108%5Cpm%20%282.33%29%5Csqrt%7B%5Cdfrac%7B0.108%281-0.108%29%7D%7B500%7D%7D%5C%5C%5C%5C%3D0.108%5Cpm2.33%5Ctimes0.013880634%5C%5C%5C%5C%3D0.108%5Cpm0.03234187722%5C%5C%5C%5C%5Capprox0.108%5Cpm0.032%3D%280.108-0.032%2C%5C%200.108%2B0.032%29%3D%280.076%2C%5C%200.140%29)
Hence, the 98% confidence interval for the true percentage of Independents among Haywards 50,000 registered voters.= (0.076, 0.140)
Answer: 9.4
a² + b² = c²
5² + 8² = c²
25+64=c²
89 = c²
√89 = √c²
9.4 = c
Step-by-step explanation:
$31+50%
31*.5=$15.50
The priceof markup is $15.50
Answer:
subtract 7.13 and 6.2 and you will get your answer
Step-by-step explanation:
Im doing the assignment on Edgenuity
and i passed hope this helps:)