25 cubic centimeters....
Hope this helps! all you had to do it multipley <span />
Answer:
1. The right answer is stay the same.
In a healthy subject, a diet rich in sugar (such as starch and fast sugars) increases blood sugar in the first two hours after ingestion and then stabilizes after the third hour with the action of the patient. insulin which has a hypoglycemic action. But over time the pancreas (the organ that secretes insulin) will get tired over time if these foods are eaten excessively.
2. The right answer is stay the same.
In a healthy person, a diet of low-sugar foods (such as fiber) does not increase blood glucose (or very little) and helps maintain normal blood glucose levels. These foods are good for the health because they preserve the pancreas as long as there is not much solicitude by the presence of a hause of glucose in the blood.
3. The right answer is increase.
In a type 1 diabetic patient, the pancreas does not secrete insulin appropriately, and this is due to self-destruction of the organ by the immune system (autoimmune disease). This implies that during the ingestion of foods rich in sugars, the blood sugar will be hard to regain its normal level, that is why it remains elevated after three hours after ingestion.
4. The right answer is stay the same.
Foods low in carbohydrates are very good for the health and is recommended in the subjects diabetic (type 1 and 2) and even for the healthy subjects to avoid the appearance of the diabetes afterwards. These foods help diabetics to have controlled blood glucose levels when their degradation does not give glucose.
Answer:
1 1/3
Step-by-step explanation:
2(8/12)=16/12=1 4/12=1 1/3
Using the slip and slide method:
2x^2+5x-12
x^2+5x-24
(x+8)(x-3)
(x+8/2)(x-3/2)
(x+4)(2x-3)
Final answer: (2x-3)(x+4)
Answer:
b/(b+a)
Step-by-step explanation:
(1/a)-(1/b) :[ (b²-a²)/ab²]
first solve :
common denominator ab
(1/a)-(1/b) = (b-a)/ab
[b-a/ab] : [(b²-a²)/ab²]
when divide fraction ( division sign turn to (×) and flip the second fraction(reciprocal):
[b-a/ab] × [ab²/ (b²-a²)]
then simplify : ab²/ab = b
(b-a)×(b/b²-a²)
factorize : b²-a² = (b-a)(b+a)
(b-a)×(b/(b-a)(b+a)) simplify : (b-a)/b-a = 1
[(b-a)(b)]/[(b-a)(b+a)
b/b+a
