Complete the number pattern for 3,400,00 34,000 ______ 3.4 _____

A random sample of n people selected from a large population will be asked whether they have read a novel in the past year. Let

kozerog [31]

Answer:

b. A binomial variable with 25 independent trials

Step-by-step explanation:

The conducted experiment is binomial experiment because outcome can be divided into success or failure. The success would be the people who read novel in the past year and also responses are independent of each other. We have to find the number of trials n in the given problem.

we are given that variance of R=6 and p=probability of success=0.4.

We know that variance of binomial distribution is

Variance=npq

where q=1-p=1-0.4=0.6.

By putting the values in variance formula, we can get the value of n.

6=n*0.4*0.6

6=0.24*n

n=6/0.24

n=25

Hence, random variable R is a binomial variable with 25 independent trials.

4 0

3 years ago

BD bisects m m Find m

amm1812

The text of the question is not visible in the answering window. I'll reproduce it here:

BD bisects <ABC.

m <ABD= 2.5x + 8.6

m<CBD = 3.5x - 3.4

Find m<ABC

Answer:

$m\angle ABC = 77.2^\circ$

Step-by-step explanation:

We have an angle ABC and a line BD bisecting it.

If an angle is bisected, then the two formed angles are congruent, that is

$m\angle ABD=m\angle CBD$

Substituting the algebraic expressions for both angles:

$2.5x + 8.6=3.5x - 3.4$

Subtracting 8.6 and 3.5x:

$2.5x - 3.5x = -8.6 - 3.4$

Operating:

$-x = -12$

$x = 12$

The two angles are:

$m\angle ABD=2.5x + 8.6=2.5(12) + 8.6=38.6^\circ$

$m\angle CBD=3.5x - 3.4 = 38.6^\circ$

As expected, both angles have the same measure.

The measure of the total angle ABC is twice any of those:

$m\angle ABC = 2*38.6^\circ=77.2^\circ$

$\mathbf{m\angle ABC = 77.2^\circ}$

6 0

3 years ago

Which expression is equivalent to (x^4/3 x^2/3)^1/3?

KATRIN_1 [288]

Answer: $x^{\frac{2}{3} }$

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

$(x^{a})(x^{b}) = x^{a + b}$ (Exponents with the same base that are being multiplied together can have the exponents added)

$(x^{a})^{b} = x^{(a)(b)}$ (A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)