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3 years ago

12

I really need this ASAP. There are 25 students in a class. How many ways can the teacher (randomly) pick two students for the le

ad roles in the class play?

1 answer:

kicyunya [14]3 years ago

4 0

Answer:

The teacher can do many different ways, I dont think there is a limited answer.

Step-by-step explanation:

If there is can you plz give me the options so I know what type of math you are doing

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Given y= 2x squared - 10x find all the real values of x for which y = -3

Thepotemich [5.8K]

$y=2 x^{2} -10x \\ -3=2 x^{2} -10x \\ 2 x^{2} -10x+3=0 \\ x=\frac{-b \pm \sqrt{ b^{2} -4ac} }{2a}, \ where \ a=2, \ b=-10, \ c=3$
Therefore,
$x=\frac{-(-10) \pm \sqrt{ (-10)^{2} -(4 \times 2 \times 3)} }{2 
\times 2} \\ =\frac{10 \pm \sqrt{ 100 -24} }{4} \\ =\frac{10 \pm \sqrt{ 
76} }{4} \\= \frac{10 + \sqrt{ 76} }{4} \ or \ \frac{10 - \sqrt{ 76} 
}{4} \\ =4.679 \ or \ 0.3206$

8 0

3 years ago

Another question this math is not my favorite ? Struggling but son what understanding it . Help please

Evgen [1.6K]

12/3= 4 <-- This equation shows that one box will benefit 4 children.
24/4=6 <-- This equation shows how many boxes will benefit 24 children.

Therefore, Raymond should buy 6 boxes.

5 0

3 years ago

The access code for a garage door consists of three digits. Each digit can be any number from 1 through 5, and each digit can b

Papessa [141]

Answer:

(a) 125

$(b) \dfrac{1}{125}$

$(c) \dfrac{124}{125}$

Step-by-step explanation:

We are given that access code consists of 3 digits.

Each digit can be any digit through 1 to 5 and can be repeated.

Now, this problem is equivalent to the problem that we have to find:

The number of 3 digit numbers that can be formed using the digits 1 to 5 with repetition allowed.

(a) We have 3 places here, unit's, ten's and hundred's places respectively and each of the 3 places have 5 possibilities (any digit allowed with repetition).

So, total number of access codes possible:

$5\times 5 \times 5 = 125$

(b) Suppose, an access code is randomly selected, what is the probability that it will be correct.

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, only 1 code is correct, so

Number of favorable cases = 1

Total number of cases = 125

So, required probability:

$P(E) = \dfrac{1}{125}$

(c) Probability of not selecting the correct access code on first time:

$P(\overline E) = 1-P(E)\\\Rightarrow P(\overline E) = 1-\dfrac{1}{125}\\\Rightarrow P(\overline E) = \dfrac{125-1}{125}\\\Rightarrow P(\overline E) = \dfrac{124}{125}$

So, the answers are:

(a) 125

$(b) \dfrac{1}{125}$

$(c) \dfrac{124}{125}$

7 0

3 years ago

How many zeros are in the simplified expression 4×10×

Lesechka [4]

one zero

hope it helped if i didn't please write back and ill try my best for further explanation

5 0

3 years ago

Read 2 more answers

Which angle is supplementary to DFA?

lisabon 2012 [21]

Answer:

<AFB

Step-by-step explanation:

Supplementary angles are the angles that's sum up to 180° which is called a straight angle.

In this question we see AFB is supplementary to DFA for DFB is the straight angle.

6 0

3 years ago