The linear equation:
y = k x + b
We will use first two values and solve the system of equations:
11 = k * 7 + b / *(-1)
13 = k * 8 + b
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-11 = - k * 7 - b
13 = k * 8 + b
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2 = k
13 = 16 + b
b = 13 - 16 = -3
y = 2 x - 3 ( y varies directly with x )
2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
We can use quadratic formula to determine the roots of the given quadratic equation.
The quadratic formula is:

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7
Using the values, we get:
So, the correct answer to this question is option A
Answer: A. x ≤ -3
x/3 - x-1/2 ≥ 1 would make x ≤ -3
Answer:
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Step-by-step explanation: