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nalin [4]
2 years ago
12

Solve the inequality Z-2>2 Z > 2?

Mathematics
1 answer:
Troyanec [42]2 years ago
5 0

Answer:

Z> 4

So Z> 2 is true

Step-by-step explanation:

Given that:

Z-2>2

Adding 2 on both sides

Z-2 + 2 >2 + 2

Z > 4

hence the equation Z > 2 is true

i hope it will help you!

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3) An existing track is perpendicular to y=1/2x + 2 and passes through B(7,5)
stira [4]

Answer:

2. y=\frac{1}{2}x +3

Step-by-step explanation:

2. The line will be parallel to the current track which means they have the same slope. To write the equation, use the slope m=1/2 and the point (2,4) in point slope form:

y-y_1=m(x-x_1)\\y-4=\frac{1}{2}(x-2)

This is the equation of the line. You can convert it to slope intercept form:

y-4=\frac{1}{2}(x-2)\\y-4 = \frac{1}{2}x -1 \y=\frac{1}{2}x +3

8 0
3 years ago
You are at a European beach with 60 other visitors. 36 of them speak English. If you randomly meet two people on the beach, what
Kaylis [27]

Answer:

Assuming I'm one of the 36 English speakers and the other 24 speak Spanish for illustration purposes.  The problem can be modeled as 59 marbles with 35 E and 24 S marbles as N = 59 possible outcomes = n(E) + n(S) = 35 + 24.

So I reach into the pile of marbles (on the beach) and the probability that it's p(E) = n(E)/N = 35/59 = 0.593220339 when I meet the one person. ANS

I assume I remember that first person; so I remove him from the marbles (by avoiding him on the beach) and now my probability is p(E and E) = n(E)/N * n(E)-1/(N - 1) = 35/59*34/58 = 0.347749854 ANS

Following the same logic p(E and E and E) = 35/59*34/58*33/57 = 0.201328863 ANS

This last one is different from the first three.  This one is p(E >= 1|4 attempts).  We can trace out a probability tree to identify those branches that contain at least one E event.  So:

EEEE p() = 35/59 * 34/58 * 33/57 * 32/56 =  

EEES p() = 35/59 * 34/58 * 33/57 * 24/56 =

EESE p() = 35/59 * 34/58 * 24/57 * 33/56 =

ESEE p() = 35/59 * 24/58 * 34/57 * 33/56 =

SEEE p() = 24/59 * 35/58 * 34/57 * 33/56 =

EESS p() = 35/59 * 34/58 * 24/57 * 23/56 =

ESES p() = 35/59 * 24/58 * 34/57 * 23/56 =

SEES

SESE

SSEE

ESSS  And so on, but...a big BUT...why do all this when

SESS

SSES

SSSE

SSSS

p(E>=1|4) = 1 - p(S and S and S and S) = 1 - 24/59 * 23/58 * 22/57 * 21/56 = 0.976652619   ANS.  In other words we find the probability of not meeting an Englishman and take 1 minus that value to find the probability of meeting at least one.

00

Step-by-step explanation:

3 0
2 years ago
Giving brainliest to first answer!!
almond37 [142]

Answer:

6

Step-by-step explanation:

6 0
2 years ago
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How many 1.4 meter sections of rope can be cut from a length of rope 6 meters long?
den301095 [7]
8.4 you mupitly 1.4*6 you will get this answer plz mark brainlest 
4 0
2 years ago
I GIVEEEE BRAINLILST
Nitella [24]

Answer:

Step-by-step explanation:

A for sure

7 0
3 years ago
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