Answer: The expected value of this game is 2/3
Step-by-step explanation:
Give that
If it's black, you lose a point. If it's red, you gain a point.
And then you can stop at any time. But you should never stop when you are losing because that can guarantee 0 by drawing all the cards.
Assuming you should stop after three cards when you are +2.
The only question is whether to draw if you are +1 on the first draw.
If you draw red first, You have 1/3 chance of drawing red again and this will give you +2 points
1/3 chance of drawing two blacks and earn zero point, chance of drawing black-red and earn +1. This gives +1, so it doesn't matter whether you draw or not.
From the beginning, If you draw red (probability 1/2 you end +1. If you draw black and then draw two reds (probability 1/6 you end +1) Otherwise you break even with probability 1/3. Overall, the value is 2/3
-4p+1 = -4(2)+1 = -8+1 = -7
In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
The answer is A please Mark as brainless