Answer:
27KG
Step-by-step explanation:
Mouse- M , Cat - C, Dog - D
M + C = 10 ----- (1)
M + D = 20 -------(2)
C + D = 24 --------(3)
(1) - (2) => C - D = -10 ---- (4)
(3) + (4) => 2C = 14
=> C = 7
Substitute C in (1) => M + 7 = 10
=> M = 3
Substitute M in (2) => 3 + D = 20
=> D = 17
Therefore C + M + D = 7 + 3 + 17 = 27KG
Answer:
12/17 miles
Step-by-step explanation:
Make the denominators equal -> 1/4 = 17/68, 3/34 = 6/68
17/68 inches represent 2 miles
The ratio between 17/68 and 6/68 is 17/68 : 6/68 = 17/6
So, the ratio between the distance should also be 17/6
-> 3/34 inches represent 2 : 17/6 = 12/17 (miles)
Hope it helps :)
Answer:
The net forces exerted on the horse and cart are not the same, so they are not balanced forces.
Step-by-step explanation:
Please see the Newton's 2nd Law which states that an object accelerates if there is a net or unbalanced force on it. In this scenario there is just one force exerted on the wagon i.e: the force that the horse exerts on it. The wagon accelerates because the horse pulls on it. And the amount of acceleration equals the net force on the wagon divided by its mass.
As there are two forces the push and pull the horse; the wagon pulls the horse backwards, and the ground pushes the horse forward. The net force is determined by the relative sizes of these two forces.
If the ground pushes harder on the horse than the wagon pulls, there is a net force in the forward direction, and the horse accelerates forward, and if the wagon pulls harder on the horse than the ground pushes, there is a net force in the backward direction, and the horse accelerates backward.
If the force that the wagon exerts on the horse is the same size as the force that the ground exerts, the net force on the horse is zero, and the horse does not accelerate.
