6 √3. Short leg is half the hypotenuse is 6 so x = long leg so x= short leg times √3
Y ^(-2/3)^-6 = y^12/3 = y^4
x^(1/2)^ -6 = x^-3 = 1 x^3
so the answer is y^4 * 1 /x^3 = y^4 / x^3
A
Answer: x=8/27 +1/27 •log(downward 5)(6)
Answer:
305.78 in2
Step-by-step explanation:
The rocket has two parts: one is a cylinder and the other is a cone.
To find the total volume of the rocket, we need to find firstly the volume of each part.
The cylinder has a radius of 2 inches and a height of 2*12 + 5 - 7 = 22 inches, so its volume is:
V1 = pi * r^2 * h = pi * 2^2 * 22 = 276.46 in2
The cone has a radius of 2 inches and a height of 7 inches, so its volume is:
V2 = (1/3) * pi * r^2 * h = (1/3) * pi * 2^2 * 7 = 29.32 in2
Then, we have that the volume of the rocket is:
V = V1 + V2 = 276.46 + 29.32 = 305.78 in2
