Answer:
<u>Given :</u>
length offshore = CS=√(1+X^2)
Cable charged = 5000√(1+X^2)
onshore length = 4-X
laying cost = 3000(4-X)
total cost:
C=5000√(1+X^2) +3000(4-X)
DC/DX
= [5000*(0.5)*2X/{√(1+X^2)}]-3000=0... for optimum
5000X=3000√(1+X^2)
25X^2=3+3X^2
22X^2=3
X=√(3/22)
= 0.3693 miles
So, it would be laid offshore to S in a manner that
BS=X=0.3693 miles
Onshore=4-0.3693
=3.6307 miles
Answer:
∠SQR = 1/2 m ∠SR = 1/2 x 86 = 43°
Answer:
Mehrangarh Fort.
Amber Fort. Located on the outskirts of Jaipur, the Amber Fort (also known as the Amer Fort) is a landmark of phenomenal beauty. ...
Jaisalmer Fort.
Step-by-step explanation:
Answer:
x > 1/4
Step-by-step explanation:
Answer:
e.none of these
Step-by-step explanation:
Computations For CC for Fraction defective
Sample No d p=d/100
1 0 0
2 0 0
3 2 0.02
4 1 0.01
5 0 0
6 1 0.01
7 2 0.02
8 0 0
Total 0.06
3 sigma control limits for p chart are given by:
hence option e is correct
