The answer is c, relying on renewable energy sources
N = 3
O = -2
1(3) +2(-2)= -1
Answer:
M1 = 49.04 g/mol
Explanation:
The pure benzonitrile has freezing point -12.8°C. By adding a nonvolatile compound, the freezing point will be changed, a process called cryoscopy. The freezing point will be reduced. In this case, the new freezing point is -13.4°C. The variation at the temperature can be calculated by the equation:
ΔT = Kc*W*i
Where ΔT is the variation at the freezing temperature (without the solute less with the solute), Kc is the cryoscopy constant (5.34 for benzonitrile), W is the molality, and i the Van't Hoff correction factor, which is 1 for benzonitrile.
((-12.8-(-13.4)) = 5.34*W
5.34W = 0.6
W = 0.1124 mol/kg
W = m1/M1*m2
Where m1 is the mass of the solute (in g), M1 is the molar mass of the solute (in g/mol), and m2 is the mass of the solvent (in kg).
m1 = 0.551 g, m2 = 0.1 kg
0.1124 = 0.551/M1*0.1
0.01124M1 = 0.551
M1 = 49.04 g/mol
Answer:
B
Explanation:
It's B because the first trial of an experiment may not always be right so you want to run multiple trials
<u>Answer:</u> The number of molecules of ethinyl estradiol present in one pill are 
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of ethinyl estradiol = 0.038 mg =
(Conversion factor: 1 g = 1000 mg)
Molar mass of ethinyl estradiol ![(C_{20}H_{24}O_2)=[(20\times 12)+(24\times 1)+(2\times 16)]=296g/mol](https://tex.z-dn.net/?f=%28C_%7B20%7DH_%7B24%7DO_2%29%3D%5B%2820%5Ctimes%2012%29%2B%2824%5Ctimes%201%29%2B%282%5Ctimes%2016%29%5D%3D296g%2Fmol)
Putting values in above equation, we get:

According to mole concept:
1 mole of a compound contains
number of molecules
So,
of ethinyl estradiol will contain =
number of molecules
Hence, the number of molecules of ethinyl estradiol present in one pill are 