Answer:
56.82 Kg
Explanation:
Given data:
1 Kg = 2.20 lbs
Number of kilogram in 125 lbs = ?
Solution:
lbs is used for pound. lb is abbreviation of libra. It is Latin word meaning balance.
Both kilogram and pounds are units of mass. Pound is smaller unit than kilogram.
one Kg = 2.20 lbs
Number of kg in 125 lbs:
125 lbs × 1 Kg/2.20 lbs
125 lbs.Kg/2.20 lbs
56.82 Kg
Answer: HOPE THIS HELPED! :D
Water vapor is the most abundant and dominant GHG in the atmosphere. Its concentration depends on temperature and other meteorological conditions, and not directly upon human activities.
Explanation:
When you bring two objects of different temperature together, energy will always be transferred from the hotter to the cooler object. The objects will exchange thermal energy, until thermal equilibrium<span> is reached, i.e. until their temperatures are equal. We say that </span>heat<span>flows from the hotter to the cooler object. </span><span>Heat is energy on the move.</span> <span>
</span>Units of heat are units of energy. The SI unit of energy is Joule. Other often encountered units of energy are 1 Cal = 1 kcal = 4186 J, 1 cal = 4.186 J, 1 Btu = 1054 J.
Without an external agent doing work, heat will always flow from a hotter to a cooler object. Two objects of different temperature always interact. There are three different ways for heat to flow from one object to another. They are conduction, convection, and radiation.
One way of knowing that oxygen was the gas removed from the volume of air and not another is to know what the volume of air is made of first. When the composition of the volume of air is already identified, then next would be the process of separating these elements from each other and as to which is to be separated first. This would usually lead to knowing their masses, their boiling and freezing points, the temperatures at which they condense, and so on. This is to identify their differences to each other and use those differences to successfully separate those elements to each other.
To calculate for the final temperature, we need to remember that the heat rejected should be equal to the absorbed by the other system. We calculate as follows:
Q1 = Q2
(mCΔT)1 = (mCΔT)2
We can cancel m assuming the two systems are equal in mass. Also, we cancel C since they are the same system. This leaves us,
(ΔT)1 = (ΔT)2
(T - 80) = (0 - T)
T = 40°C
