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max2010maxim [7]
3 years ago
9

A particular oral contraceptive contains 0.038 mg of ethinyl estradiol in each pill. The formula of this compound is C20H24O2. H

ow many molecules of ethinyl estradiol are there in one pill?
Chemistry
1 answer:
Ray Of Light [21]3 years ago
5 0

<u>Answer:</u> The number of molecules of ethinyl estradiol present in one pill are 7.71\times 10^{16}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethinyl estradiol = 0.038 mg = 3.8\times 10^-5}g    (Conversion factor: 1 g = 1000 mg)

Molar mass of ethinyl estradiol (C_{20}H_{24}O_2)=[(20\times 12)+(24\times 1)+(2\times 16)]=296g/mol

Putting values in above equation, we get:

\text{Moles of ethinyl estradiol}=\frac{3.8\times 10^{-5}g}{296g/mol}=1.28\times 10^{-7}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 1.28\times 10^{-7}mol of ethinyl estradiol will contain = (1.28\times 10^{-7}\times 6.022\times 10^{23})=7.71\times 10^{16} number of molecules

Hence, the number of molecules of ethinyl estradiol present in one pill are 7.71\times 10^{16}

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First, we have to get:

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In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

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By replacing the corresponding values we obtain:

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