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3 years ago

We can preserve natural resources by

Chemistry

1 answer:

DedPeter [7]3 years ago

3 0

The answer is c, relying on renewable energy sources

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HELP ASAP

vitfil [10]

Looking at the following answers, and considering the definition of a biological community I believe the answer is D.

8 0

3 years ago

Read 2 more answers

How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci

horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

5 0

3 years ago

What is highly reactive to water and forms an ionic bond with chlorine? It’s very shiny.

34kurt

Is this multiple choice?<span />

3 0

3 years ago

How do you know if the reaction is exothermic

MArishka [77]

Hey there!
Exothermic reactions release heat, causing its temperature to fall. If the reaction is lessening the temperature of the object while releasing all the heat, then you know that the reaction is indeed exothermic. Hope this helps!

5 0

3 years ago

How many milliliters of 0.0896M LiOH are required to titrate 25.0 mL of 0.0759M HBr to the equivalence point?

slavikrds [6]

Answer:

$V_{LiOH}=21.8mL$

Explanation:

Hello,

In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:

$n_{LiOH}=n_{HBr}$

That it terms of molarities and volumes we have:

$M_{LiOH}V_{LiOH}=M_{HBr}V_{HBr}$

Next, solving for the volume of lithium hydroxide we obtain:

$V_{LiOH}=\frac{M_{HBr}V_{HBr}}{M_{LiOH}} =\frac{0.0759M*25.0mL}{0.0896M} \\\\V_{LiOH}=21.8mL$

Best regards.

8 0

2 years ago