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3 years ago

Which statement is true of any chemical reaction?

Chemistry

1 answer:

klemol [59]3 years ago

4 0

According to the Law of Conservation of Mass,

The mass of the products in a chemical reaction must equal the mass of the reactants.

∴ D is the Answer

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The density of water at 40°c is 0.992 g/ml. what is the volume of 3.45 g of water at this temperature?

wariber [46]

3.45÷0.992=3.48ml
...

8 0

3 years ago

When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat

UNO [17]

Answer:

See Explanation

Explanation:

Given

(a) to (d)

Required

Determine whether the given parameters can calculate the required parameter

To calculate either Density, Mass or Volume, we have

$Density = \frac{Mass}{Volume}$

$Mass = Density * Volume$

$Volume = \frac{Mass}{Density}$

(a) 432 g of table salt occupies 20.0 cm^3 of space

Here, we have:

$Mass = 432g$

$Volume = 20.0cm^3$

The above can be used to calculate Density as follows;

$Density = \frac{Mass}{Volume}$

$Density = \frac{432g}{20.0cm^3}$

$Density = 21.6g/cm^3$

(b) 5.00 g of balsa wood, density of balsa wood : 0.16 g/cm^3

Here, we have:

$Mass = 5.00g$

$Density = 0.16g/cm^3$

This can be used to solve for Volume as follows:

$Volume = \frac{Mass}{Density}$

$Volume = \frac{5.00g}{0.16g/cm^3}$

$Volume = 31.25cm^3$

(c) 32 cm^3 sample of gold density of 19.3 g/cm^3

Here, we have:

$Volume = 32cm^3$

$Density = 19.3g/cm^3$

This can be used to calculate Mass as follows:

$Mass = Density * Volume$

$Mass = 32cm^3 * 19.3g/cm^3$

$Mass = 617.6g$

(d) 150 g of iron, density of Iron = 79.0 g/cm^3

Here, we have

$Mass = 150g$

$Density = 79.0g/cm^3$

This can be used to calculate volume as follows:

$Volume = \frac{Mass}{Density}$

$Volume = \frac{150g}{79.0g/cm^3}$

$Volume = 1.90 cm^3$ Approximated

5 0

3 years ago

What is the balanced equation for the manufacture of ethanol from glucose

Darina [25.2K]

Answer:

C6H12O6 → 2C2H5OH + 2CO2

Explanation:

Glucose is an organic molecule, specifically a sugar, with the formula C612O6 while ethanol is another organic molecule with formula; C2H5OH.

However, as rightly said in this question, ethanol can be got from glucose via a process called fermentation in the presence of a catalyst called YEAST. The balanced equation is as follows:

C6H12O6 → 2C2H5OH + 2CO2

7 0

3 years ago

Dihydrogen dioxide decomposes into water and oxygen gas. Calculate the amounts requested if 1.34 moles of dihydrogen dioxide rea

a_sh-v [17]

Answers:

a. Moles of oxygen formed: 0.670 mol

b. Moles of water formed: 1.34 mol

c. Mass of water formed: 24.1 g

d. Mass of oxygen formed: 21.4 g

Explanation:

Dihdyrogen dioxide is the chemical name for a compound made of two hydrogen atoms and two oxide atoms, i.e. H₂O₂, which is also known as hydrogen peroxide or oxygenated water.

The decomposition reaction of dihydrogen dioxide into water and oxygen gas is represented by the balanced chemical equation:

$2H_2O_2(l)\rightarrow 2H_2O(l)+O_2(g)$

The mole ratios derived from that balanced chemical equation are:

2 mol H₂O₂ : 2 mol H₂O : 1 mol O₂

a. Moles of oxygen formed

Set the proportion using the theoretical mole ratio of H₂O₂ to O₂ and the amount of moles of dyhydrogen dioxide that react:

$2\text{ mol }H_2O_2/1\text{ mol }O_2=1.34\text{ mol }H_2O_2/x$

When you solve for x, you get:

x = 1.34 mol H₂O₂ × 1 mol O₂ / 2 mol H₂O₂ = 0.670 mol O₂

b. Moles of water formed

Set the proportion using the theoretical mole ratio of H₂O₂ to H₂O and the amount of moles of dyhydrogen dioxide that react:

$2\text{ mol }H_2O_2/2\text{ mol }H_2O=1.34\text{ mol }H_2O_2/x$

When you solve for x, you get:

x = 1.34 mol H₂O₂ × 2 mol H₂O / 2 mol H₂O₂ = 1.34 mol H₂O

c. Mass of water formed

Using the number of moles of water calculated in the part b., you calculate the mass of water formed, in grams, using the molar mass of water:

Molar mass of water = 18.015 g/mol

Number of moles = mass in grams / molar mass

⇒ mass in grams = number of moles × molar mass

⇒ mass in grams = 1.34 mol × 18.015 g/mol = 24.1 g

d. Mass of oxygen formed

Using the number of moles of oxygen determined in the part a., you calculate the mass in grams using the molar mass of O₂.

Molar mass of O₂ = 32.00 g/mol

mass = molar mass × number of moles

mass = 32.00 g/mol × 0.670 mol = 21.4 g.

5 0

3 years ago

What type of sand dunes will likely form if the sand supply is limited, the wind direction is constant, and vegetation is sparse

8_murik_8 [283]

The answer is........barchan dunes

3 0

3 years ago