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Strike441 [17]
3 years ago
7

When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat

ionship between those units so you will know how to set up your equation in order to solve the problem. Review the data sets below and use the steps of the problem-solving method to determine whether the given measurements would be appropriate for calculating mass, volume, or density.
a. 432 g of table salt occupies 20.0 cm^3 of space
b. 5.00 g 0T balsa wood, density of balsa wood : 0.16 g/cm^3
c. 32 cm^3 sample of gold density of gold 19.3 =g/cm^3
d. 150 g of iron, density of Iron = 79.0 g/cm^3
Chemistry
1 answer:
UNO [17]3 years ago
5 0

Answer:

See Explanation

Explanation:

Given

(a) to (d)

Required

Determine whether the given parameters can calculate the required parameter

To calculate either Density, Mass or Volume, we have

Density = \frac{Mass}{Volume}

Mass = Density * Volume

Volume = \frac{Mass}{Density}

(a) 432 g of table salt occupies 20.0 cm^3 of space

Here, we have:

Mass = 432g

Volume = 20.0cm^3

The above can be used to calculate Density as follows;

Density = \frac{Mass}{Volume}

Density = \frac{432g}{20.0cm^3}

Density = 21.6g/cm^3

(b) 5.00 g of balsa wood, density of balsa wood : 0.16 g/cm^3

Here, we have:

Mass = 5.00g

Density = 0.16g/cm^3

This can be used to solve for Volume as follows:

Volume = \frac{Mass}{Density}

Volume = \frac{5.00g}{0.16g/cm^3}

Volume = 31.25cm^3

(c) 32 cm^3 sample of gold density of 19.3 g/cm^3

Here, we have:

Volume = 32cm^3

Density = 19.3g/cm^3

This can be used to calculate Mass as follows:

Mass = Density * Volume

Mass = 32cm^3 * 19.3g/cm^3

Mass = 617.6g

(d) 150 g of iron, density of Iron = 79.0 g/cm^3

Here, we have

Mass = 150g

Density = 79.0g/cm^3

This can be used to calculate volume as follows:

Volume = \frac{Mass}{Density}

Volume = \frac{150g}{79.0g/cm^3}

Volume = 1.90 cm^3 <em>Approximated</em>

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Answer:

0.0344 moles and 1.93g.

Explanation:

Molarity is defined as the ratio between moles of a solute (In this case, KOH), and the volume. With molarity and volume we can solve the moles of solute. With moles of solute we can find mass of the solute as follows:

<em>Moles KOH:</em>

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3 years ago
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Answer:

'See Explanation

Explanation:

Determine the [OH−] , pH, and pOH of a solution with a [H+] of 9.5×10−13 M at 25 °C.

Given [H⁺] = 9.5 x 10⁻¹³M => [H⁺][OH⁻] = 1.0 x 10⁻¹⁴ => [OH⁻] = 1.0 x 10⁻¹⁴/9.5 x 10⁻¹³ = 0.0105M

pH = -log[H⁺] = -log(9.5 x 10⁻¹³) = - (-1202) = 12.02.

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How many moles of water can be obtained from the reaction of 4 moles of O2?
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Answer: 8moles

Explanation:

The reaction below shows the formation of 2 moles of water from 2 moles of hydrogen and 1 mole of oxygen respectively.

2H2(g) + O2 (g) --> 2H2O(l)

So, if 1 mole of O2 produce 2 mole of H2O

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How many kilojoules of heat are needed to completely vaporize 42.8 grams of c4h10o at its boiling point given that c4h10o has a
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Answer is: 15.30 kilojoules of heat are needed to completely vaporize C₄H₁₀<span>.
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M(C₄H₁₀) = 74.12 g/mol.
n(C₄H₁₀) = m(C₄H₁₀) ÷ M(C₄H₁₀).
n(C₄H₁₀) = 42.8 g ÷ 74.12 g/mol.
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<span>Q = 0.577 mol </span>· 26.5 kJ/mol.
<span>Q = 15.30 kJ, heat of butane.

</span>
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