Answer:
1
2
6
Step-by-step explanation:
1/2 +1/2 =1
length 1/2 ×4=2
wide 1/2 ×3 =1 1/2
height 1/2×3= 1 1/2
I can only assume that you meant, "Solve for x:"
Apply the exponent 3/2 to both sides of this equation. The result will be
3/2
343 = x/6.
Multiplying both sides by 6 isolates x:
3/2
6*343 = x Since 7^3 = 343, the expression for x
can be rewritten as
3/2
6*(7^3) = x which can be further simplified, as follows:
x = 6^(3/2)*7^(9/2), or:
x = 6^(3/2)*7^(8/2)*√7, or
x = 6^(3/2)*7^4*√7
Answer:

Step-by-step explanation:
Given



Required
The volume of the remaining cylinder
Before the cut-out, the cylinder has a volume (V) of:

After the cut-out, the cylinder has a volume of:
![V = \pi [R^2 -r^2]h](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%5BR%5E2%20-r%5E2%5Dh)
So, we have:
![V = 3.14* [6^2 -5^2]*15](https://tex.z-dn.net/?f=V%20%3D%203.14%2A%20%5B6%5E2%20-5%5E2%5D%2A15)
![V = 3.14* [36 -25]*15](https://tex.z-dn.net/?f=V%20%3D%203.14%2A%20%5B36%20-25%5D%2A15)


9514 1404 393
Answer:
(x, y) = (3, 0)
Step-by-step explanation:
The solution space is above the line y = -x+2 in the right half-plane where x > 0. One possible solution is (x, y) = (3, 0).
Answer:
The dimension of the cardboard is 34 cm by 34 cm by 17 cm.
Step-by-step explanation:
Let the dimension of the cardboard box be x cm by y cm by z cm.
The surface area of the cardboard box without lid is
f(x,y,z)= xy+2xz+2yz.....(1)
Given that the volume of the cardboard is 19,652 cm³.
Therefore xyz =19,652
......(2)
putting the value of z in the equation (1)


The partial derivatives are


To find the dimension of the box set the partial derivatives
and
.Therefore 
.......(3)
and 
.......(4)
Now putting the x in equation (3)



⇒y=34 cm
Then
=34 cm.
Putting the value of x and y in the equation (2)

=17 cm.
The dimension of the cardboard is 34 cm by 34 cm by 17 cm.