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laila [671]
2 years ago
13

Given the following function, find f(-2), f(0), and f(1). f(x) = x2 + 3 =

Mathematics
2 answers:
WARRIOR [948]2 years ago
7 0

Answer:

jjjjnnuiuhjiihhiihb

Step-by-step explanation:

tyuijiojnoo.

yu8ijhiihj

Dennis_Churaev [7]2 years ago
5 0
The answer to f(-2) is -1. F(0) is 3. F(1) is 5.

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Determine the surface area of a sphere with radius 2 meters. Question 12 options: A) 24.2 m2 B) 16 m2 C) 50.3 m2 D) 32 m2
Nady [450]

Answer:

C

Step-by-step explanation:

SA=4*pi*r^2

SA=4*pi*2^2

SA=4*pi*4

SA=16*pi m^2

SA≈50.2654824574

SA≈50.3 m^2

Which is C

5 0
3 years ago
Select the correct answer.
SVEN [57.7K]
Select the correct answer.
If a = 0.3 and b =0.5, what is the value of a+b?
A.8/10
B.8/9
C.80/99
D.88/100

Hey Love!<3 It would be

A.8/10
3 0
2 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
2 years ago
Use the information provided to answer Part A and Part B. A store owner paid \$ 15$15 for a book. She marked up the price of the
Ymorist [56]

Answer City's breaking down on a camel's back

7 0
1 year ago
Can someone tell me some word problems already solved? dividing and multiplying decimals and integers by 100,10 and 1000. I need
const2013 [10]

Answer:

wait im a little confused sorry but im going to try my best

Step-by-step explanation:

50x2=100. 5×2=10. 500x2=1,000

1,000÷10=100. 100÷10=10. 10,000÷10=1,000

5 0
2 years ago
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