D= sqrt( (6-4)^2 + (5sqrt2 - 3sqrt2)^2 )
It's d= 3,46 i think
Answer:
I am led to believe the answers are 4 and 1
Step-by-step explanation:
I don't think its answer 2 because thou are radios and their isn't any fractions in it
I solved answer 4 it came as a fraction
Okay i looked at 1 and i did all of them they all came out as a decimal so i think that's another one
answer 3 you can't divide by 0 so i don't think so
For this problem, we use the approach of ratio and proportion. Assuming that the given ratio of 444 days per 230 km is constant all throughout, we can determine the number of days or distance as long as one of the two is given. In this case, the solution is as follows:
444 days/230 km = 161616 days/distance
Distance = 83,720 km
Answer:
8/15
Step-by-step explanation:
you first want to change your whole number, 4, into a fraction so all you have to do is add a 1 in the denominator so it will be 4/1
then you multiply across
2/15 * 4/1
you first multiply 2 and 4 and your answer will be 8 which is the numerator
then multiply 15 and 1 which is 15, the denominator
then you get
8/15
Answer:
We are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%
Step-by-step explanation:
-From the given information, 
.
-We calculate the confidence interval using this value at 95% confidence level:
![CI=\hat p\pm z \sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\\\=0.65\pm 1.96\times \sqrt{\frac{0.65\times 0.35}{12000}}\\\\\\=0.65\pm 0.0085\\\\\\=[0.6415,0.6585]](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%5C%5C%5C%5C%5C%5C%3D0.65%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.65%5Ctimes%200.35%7D%7B12000%7D%7D%5C%5C%5C%5C%5C%5C%3D0.65%5Cpm%200.0085%5C%5C%5C%5C%5C%5C%3D%5B0.6415%2C0.6585%5D)
So, the 95% confidence interval is (0.6515,0.6585).
Hence, we are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%.
