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2 years ago

Find the distance between the points (6, 5 √2.) and (4, 3 √2).

Mathematics

2 answers:

Darya [45]2 years ago

7 0

Answer:

2 square root of 3!

Step-by-step explanation:

Natali5045456 [20]2 years ago

5 0

D= sqrt( (6-4)^2 + (5sqrt2 - 3sqrt2)^2 )

It's d= 3,46 i think

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12-22 plz help thanks

Kisachek [45]

12-22 = -10 because know I'm right and it says I have to put more words so just look at the first part

6 0

2 years ago

Having a hard time with this

raketka [301]

Answer:

the correct answer is D

Step-by-step explanation:

because the -9 5/8 is in absolute value marks.

6 0

2 years ago

Write the equation of a line, in slope-intercept form<br> (1,1);(-2,-11)<br> Y =

bonufazy [111]

Answer:

Y =4X -3

Step-by-step explanation:

x1 y1 x2 y2

1 1 -2 -11

(Y2-Y1) (-11)-(1)= -12 ΔY -12

(X2-X1) (-2)-(1)= -3 ΔX -3

slope= 4

B= -3

Y =4X -3

6 0

2 years ago

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A teacher surveyed her class to find out how many texts the students send in a week. She created this box plot to show the data.

Marta_Voda [28]

Answer: 130
Explanation:

7 0

2 years ago

FIRST TO ANSWER GETS BRAINLIEST!

scZoUnD [109]

Answer:

$\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

circle
PEMDAS

<h3>tips and formulas:</h3>

$\rm \:A_{shaded}= \dfrac{\theta}{360} \times \pi {r}^{2}$

<h3>let's solve:</h3>

$\sf sustitute \: the \: value \: of \: \theta \: and \: r : \\ A_{shaded} = \frac{140}{360} \times \pi \times {8}^{2}$
$\sf simpify \: squre : \\ A_{shaded} = \frac{140}{360} \times \pi \times 64$
$\sf simpify \: fraction: \\ A_{shaded} = \frac{7}{18} \times \pi \times 64$
$\sf reduce \: 64: \\ A_{shaded} = \frac{7}{ \cancel{ \: 18} \: ^{9} } \times \pi \times \cancel{ 64} \: ^{32} \\ A_{shaded} = \frac{7}{9} \times \pi \times 32\\ A_{shaded} = \frac{224\pi}{9}$

$\large A_{shaded}\approx 78 \: square \: units$

8 0

2 years ago

Read 2 more answers