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MariettaO [177]
3 years ago
9

The average of the degree

Mathematics
1 answer:
maria [59]3 years ago
8 0
The answer is C.
Octagon is 135
And decagon is 144
So 144-135=11
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If √6 is the geometric mean between 4 and another number, then the number is<br> 1.5<br> 9<br> 24
konstantin123 [22]
Correct answer is A.

g - geometric mean
g= \sqrt{ab} &#10;\\&#10;\\g= \sqrt{6} ,a=4,b=?&#10;\\ \sqrt{6}= \sqrt{4b} &#10;\\  (\sqrt{6})^2= (\sqrt{4b} )^2&#10;\\6=4b&#10;\\&#10;\\b= \frac{6}{4} = \frac{3}{2}=1.5
4 0
3 years ago
No body helped me the last time so I’m posting it again I really need help with this
PIT_PIT [208]
B is equal to 154 degrees. we know this cause half of the circle equals 180 and if you subtract a (26) from 180 you get 154
3 0
3 years ago
Helppp!! I NEED HELP PLEASE
Elodia [21]

Given:

The table of values for the function f(x).

To find:

The values f^{-1}(f(3.14)) and f(f(-7)).

Solution:

From the given table, it is clear that the function f(x) is defined as:

f(x)=\{(-14,11),(-7,-12),(-12,-5),(9,1),(10,-2),(-2,13)\}

We know that if (a,b) is in the function f(x), then (b,a) must be in the function f^{-1}(x). So, the inverse function is defined as:

f^{-1}(x)=\{(11,-14),(-12,-7),(-5,-12),(1,9),(-2,10),(13,-2)\}

And,

f^{-1}(f(a))=f^{1}(b)

f^{-1}(f(a))=a              ...(i)

Using (i), we get

f^{-1}(f(3.14))=3.14

Now,

f(f(-7))=f(-12)

f(f(-7))=5

Therefore, the required values are f^{-1}(f(3.14))=3.14 and f(f(-7))=5.

5 0
3 years ago
Mrs. Savino runs 3 miles in 28 minutes. At this rate, how many minutes would it take her to run 15 miles? * Need it ASAP​
VashaNatasha [74]

Answer:

she would take 140 minutes to run 15 miles

Step-by-step explanation:

28 X 5 os equal to 140

7 0
3 years ago
Read 2 more answers
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ExtremeBDS [4]
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\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby &#10;\begin{array}{llll}&#10;\textit{now let's multiply both}\\&#10;\textit{sides by }\stackrel{LCD}{2}&#10;\end{array}&#10;\\\\\\&#10;2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}&#10;\\\\\\&#10;\textit{and if we multiply both sides by -1}\qquad 5x-2y=23

side note:  multiplying by the LCD of both sides is just to get rid of the denominators
5 0
3 years ago
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