Can someone help me fill out this chart
1 answer:
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Answer: 0.002718
Step-by-step explanation:
Given : The population mean annual salary for environmental compliance specialists is about $62,000.
i.e.
Sample size : n= 32
Let x be the random variable that represents the annual salary for environmental compliance specialists.
Using formula , the z-value corresponds to x= 59000 will be :
Now, by using the standard normal z-table , the probability that the mean salary of the sample is less than $59,000 :-
Hence, the probability that the mean salary of the sample is less than $59,000= 0.002718