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2 years ago

Find the perimeter of a square with sides that measure (2/3)g centimeters.

Mathematics

2 answers:

borishaifa [10]2 years ago

5 0

Answer:

Hello There!!

Step-by-step explanation:

Perimeter=>Add all the sides around the shape(outside).

A square has four sides so 2.3×4=9.2cm(don't forget the units).

hope this helps,have a great day!!

~Pinky~

BARSIC [14]2 years ago

3 0

Answer:

Perimeter of a SQUARE

4 x s

4 x 2.3 = 9.2 cm

Hence the perimeter of the square is 9.2cm

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What is the equation of the line that is parallel to y =1/5x+4

atroni [7]

Answer:

y=(1/5)x-5

Step-by-step explanation:

The given equation is

y=(1/5)x+4

This is of the form

y=mx+b

which is called the slope-intercept form because

m is the slope

b is the y intercept.

In this case,

m=1/5

b=4

you can see from the chart that this matches the red line.

If two lines are parallel, they must have the same slope. So we know that the slope of the desired line is 1/5. So, now we know that

y=(1/5)x+b

Since the line must go through the point (5,-4), we have

-4=(1/5)(5)+b

-4=1+b

b=-5

So, the desired line is

y=(1/5)x-5

7 0

2 years ago

Linda pays $24.84 for 7.2 gallons of gas.

Artemon [7]

Answer:

3.45

Step-by-step explanation:

24.84/7.2 = 3.45

5 0

1 year ago

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The product of x and 2 is less than or equal to 4

maw [93]

I think it's equal to 4, It sounds the most likely

4 0

2 years ago

(Sketch the graph x^2-7x+12=0

Nonamiya [84]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$x^{2} -7x+12=0$

This is a vertical parabola open upward (because the leading coefficient is positive)

The vertex is a minimum

step 1

Find the vertex of the quadratic equation

Convert the equation in vertex form

Complete the squares

$(x^{2} -7x+3.5^2)+12-3.5^2=0$

$(x^{2} -7x+12.25)+12-12.25=0$

$(x^{2} -7x+12.25)-0.25=0$

Rewrite as perfect squares

$(x-3.5)^{2}-0.25=0$

The vertex is the point (3.5,0.25)

step 2

Find the x-intercepts

The x-intercepts are the values of x when the value of the function is equal to zero

we have

$(x-3.5)^{2}-0.25=0$

solve for x

$(x-3.5)^{2}=0.25$

square root both sides

$(x-3.5)=\pm0.50$

$x=3.5\pm0.50$

$x=3.5+0.50=4$

$x=3.5-0.50=3$

therefore

The x-intercepts are the points (3,0) and (4,0)

step 3

Find the y-intercept

The y-intercept is the value of y when the value of x is equal to zero

we have

$y=x^{2} -7x+12$

For x=0

$y=(0)^{2} -7(0)+12$

$y=12$

The y-intercept is the point (0,12)

step 4

Graph the quadratic equation

we have

The vertex (3.5,0.25)

The x-intercepts (3,0) and (4,0)

The y-intercept (0,12)

using a graphing tool

Plot the points and draw the figure

The graph in the attached figure

3 0

3 years ago

(ANSWER ASAP)lara made the table below of the predicted values for h(t), the height, in meters, of a penny t seconds after it is

RSB [31]

We are given table for height of the a penny h(t) in meters after t seconds.

For the table we can see very first value of t is 0 that represents starting time.

We are given h(t) =2 for t=0.

So, the coin was thrown from a height 2 meter.

Now, if we observe the table the coin height is getting decrease over the number of seconds.

At time 0.6 seconds the height of the coin is 0.236 meter.

And at 0.7 seconds it's became negative, that is -0.401.

So, after 0.6 seconds it is getting near and near to the ground.

So, after 0.6 seconds it would be 0.7 second.

So, we could just say that it would it take 0.7 second the penny to hit the ground.

5 0

3 years ago

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