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AleksAgata [21]
3 years ago
15

Find the product. (a3 + 8)(a3 – 8)

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0
<h2>Answer:</h2>

Option: D is the correct answer.

The product is:

       D.    a^6-64

<h2>Step-by-step explanation:</h2>

We are asked to simplify the given algebraic expression i.e. we have to find the product of two algebraic expressions, which are a polynomial in terms of "a"

As both are cubic polynomial so there product will be a six-degree polynomial.

( Since on  multiplying the degree gets add up )

                   The expression is as follows:

                  (a^3+8)(a^3-8)

We know that:

(a+b)(a-b)=a^2-b^2

Hence we get the product as:

(a^3+8)(a^3-8)=(a^3)^2-(8)^2\\\\\\i.e.\\\\\\(a^3+8)(a^3-8)=a^6-64

                 Hence, the product is:

                        a^6-64

kogti [31]3 years ago
6 0
1. Use difference of squares: a^2-b^2=(a+b)(a-b)
(a^3)^2-8^2
2. Use power rule: (x^a)^b=x^(ab)
a^6-8^2
3. Simplify 8^2 to 64
a^6-64

Your answer is d. 
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Answer:

Step-by-step explanation:

Ratio=3:4

so,the pair of adjacent sides are 3x,4x

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7 0
3 years ago
A box contains 14 large marbles and 11 small marbles. Each marble is either green or white. 8 of the large marbles are green, an
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Answer:

Step-by-step explanation:

Given that:

Number of Large Marbles = 14

Number of Small Marbles = 11

Number of Green large marbles = 8

Number of White small marbles = 5

We can now find the number of white large marbles and green small marbles from the information stated above.

No of white large marble = total large marble minus green large marble

= 14-8

= 6

No of green small marbles = Total small marbles minus white small marble.

= 11-5

= 6

Let the following be represented

( X,Y, Z,Q ) as follows:

Let Y be the event of drawing small marble

Let X be the event of drawing large marble

Let Q be the event of drawing white marble

Let Z be the event of drawing green marble.

Since, only one marble is drawn at a time we calculate,

P( X ) = 14/25

P( Y) = 11/25

P(Z) = 14/25

P( Q) = 11/25

P(Y∪Q)=P(Y)+P(Z)−P(Y∩Z)...(1)

We need to find the value of

P(Y∩Z)

In 11 small marbles there are 6 green marbles so the value of P(Y∩Z) is given by P(Y∩Z)=6/11

Therefore, substitute the values in equation 1.

P(Y∪Z)=P(Y)+P(Z)−P(Y∩Z)=11/25+14/25-

6/11

=0.44+0.56−0.5455

= 1-0.5455

= 909/2000

= 0.4545

Then, one can conclude that the probability of drawing a small or green marble is 0.4545

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Answer:

That is a division equation.

Step-by-step explanation:

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