Answer:
(a)
(b)5,832 Mosquitoes
(c)5 days
Step-by-step explanation:
(a)Given an original amount 
at t=0. The population of the colony with a growth rate 
, where k is a constant is given as:
(b)If 
and the population after 1 day, N(1)=1800
Then, from our model:
N(1)=1800
Therefore, our model is:
In 3 days time
The population of mosquitoes in 3 days time will be approximately 5832.
(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.
From our model
In approximately 5 days, the population of mosquitoes will be 20,000.
1. Use a straightedge to draw line m and label a point on the line as point F
2. Construct a line perpendicular to line m through point F. Label a point on this line as point G.
3. With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
4. Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK.
5. Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.
6. Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
The law of logarithms is
㏒ₓᵃ =n and a=x^n
we have ㏒₃ 9=2
3 is the base
