The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
Learn more about quadratic equation:
brainly.com/question/1214333
#SPJ1
It would be 4!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
39.0625 ft
Step-by-step explanation:
Since the function is a quadratic representing height, and the coefficient of the t² is negative, the vertex of the parabola will be the maximum height achieved by the ball.
The general form for a quadratic equation is ax² + bx + c, here a is -16, and b is 50
To find the x coordinate of the vertex, use x = -b/(2a)
We have x = -50/[2(-16)]
x = -50/-32
x= 25/16
Now plug that into the equation to find the y value, which will be the height...
y = 50(25/16) - 16(25/16)²
y = 1250/16 - 16(625/256)
y = 1250/16 - 625/16
y = 625/16
y = 39.0625
Answer:
B. a^2x
Step-by-step explanation:
squaring a^x gives. (a^x)²
by applying the rules of indices, ^2 multiplies x therefore making it a^2x
Answer:
B
Step-by-step explanation:
