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3 years ago

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Find the indicated probability. A bin contains 72 light bulbs of which 10 are defective. If 5 light bulbs are randomly selected

from the bin with replacement, find the probability that all the bulbs selected are good ones. Round to the nearest thousandth if necessary. (Hint: sampling with replacement = independent events)

1 answer:

erastova [34]3 years ago

5 0

Answer:

The answer to the nearest thousandth is 0.473

Step-by-step explanation:

Number of light bulbs = 72

Number of defective light bulbs = 10

Number of good light bulbs = 72 - 10 = 62

Probability of selecting a defective light bulb = P(defective) = 10/72

The probability of selecting a good light bulb = P(good) = 62/72

5 number of light bulbs are selected with replacement and all being good is given by

P(all bulbs are good) = $(\frac{62}{72} )$ × $(\frac{62}{72} )$ × $(\frac{62}{72} )$ × $(\frac{62}{72} )$ × $(\frac{62}{72} )$ = 0.473473

The answer to the nearest thousandth is

0.473

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Answer:

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Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

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According to the problem,

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Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

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$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

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⇒r=1.71

Now,

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Therefore,

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