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Law Incorporation [45]
4 years ago
6

Please help quick thank you!

Mathematics
1 answer:
ipn [44]4 years ago
8 0

Answer:

Neither

Step-by-step explanation:

After substituting the ordered pair into the equation, none of the pairs satisfy the equation

because 6(3)+3(-2)=12 and 6(2)+3(2)=18.

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What is the value of 24 : 48?
Tanya [424]

Answer:

1/2

Step-by-step explanation:

..

3 0
3 years ago
Complete the table to investigate dialations of exponential functions.
nataly862011 [7]

Answer:

a = 1, b = 3, c = 1, d = 2, e = 6, and f = 8

Step-by-step explanation:

The given exponential functions are;

2ˣ, 3·2ˣ, and  2^{3 \cdot x}

Let f(x) = 2ˣ, h(x) = 3·2ˣ, and g(x) = 2^{3 \cdot x}

From the table for investigating the dilations of exponential function, we have;

a = f(0) = 2⁰ = 1

b = h(0) = 3·2⁰ = 3 × 1 = 3

c = g(0) = 2^{3 \times 0} = 2⁰ = 1

d = f(1) = 2¹ = 2

e = h(1) = 3·2¹ = 3 × 2 = 6

f = g(1) = 2^{3 \times 1} = 2³ = 8.

8 0
3 years ago
What is the absolute value of -7 minus 3
otez555 [7]

4 i believe

hope it helps!


8 0
3 years ago
Read 2 more answers
Christov and Mateus gave out candy to children on Halloween. They each have out candy at a constant rate, and they both gave awa
Likurg_2 [28]

Answer: 1) Both Christov and Mateus gave same number of candies to each child.

2) Christov gave candy to a greater number of children.

Step-by-step explanation:

1) Since, both have the same rate of distribution,

Therefore, Both will give same number of candies to each child.

2) Here, the initial number of candies Christov has 300

C(n)=270 - 3 n

Initially, n = 0

C(0) = 270

⇒ The initial number of candies Mateus has 270.

Since, 300 > 270

Therefore, Christov has more candies than Mateus,

Also, both have the same rate of distribution,

⇒ Christov gave candy to more children than Mateus.

⇒  Christov gave candy to a greater number of children.



5 0
4 years ago
Find the solution to the system of equations.
erica [24]

Answer:

x=1, y=3

Step-by-step explanation:

21x + 7y = 42

Divide this by 7

3x +y = 6

-5x +5y = 10

Divide this by 5

-x+y = 2

Subtract the two equations to eliminate y

3x +y = 6

-(-x+y = 2)

------------------------

3x +y = 6

+x-y = -2

------------------------

4x     = 4

Divide by 4

x = 1

Now solve for y

-x+y = 2

-1 +y = 2

Add 1 to each side

y = 2+1

y =3

3 0
3 years ago
Read 2 more answers
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