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Dvinal [7]
3 years ago
10

Amelia needs to buy some cat food. At the nearest​ store, 2 bags of cat food cost $4.50. How much would Amelia spend on 6 bags o

f cat food?
Mathematics
2 answers:
sveta [45]3 years ago
8 0
2 bags of cat food = $4.50
1 bag of cat food = $4.50/2 = $2.25
6 bags of cat food = $2.25x6 = $13.5

Amelia would spend $13.5 on cat food.
marissa [1.9K]3 years ago
7 0

Answer:

$13.50

Step-by-step explanation:

<u><em>2 bags of cat food = $4.50</em></u>

<u><em>1 bag of cat food = 2/4.50</em></u>

<u><em>= 2.25</em></u>

<u><em>6 bags of cat food = 2.25*6</em></u>

<u><em>=13.50</em></u>

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PLEASE HELPPPP!!!!!!
Sloan [31]

Step-by-step explanation:

y=kx

say that y is the original prince and x is the sale price

15=k(10)

15/10=k

3/2=k

you can check with the next problem to check if it is the same

25=k(20)

25/20=k

5/4=k

so you take 5/4-3/2=-1/4 so the constant is -1/4

Hope that helps :)

8 0
3 years ago
If f(x)=3x^2-1 and g(x)=x+2, find (f+g)(x)
algol13
Answer:
(f+g)(x) = 3x^2 + x + 1

Explanation:
We are given that:
f(x) = 3x^2 - 1
g(x) = x + 2
To find (f+g)(x), all we have to do is add the above to functions as follows:
(f+g)(x) = f(x) + g(x)
= 3x^2 - 1 + x + 2
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Hope this helps :)
5 0
3 years ago
Read 2 more answers
Determinar él área de un rectángulo que tiene un lado mayor de 8 m y un lado menor de 7 metros
Ede4ka [16]
Answer/Respuesta: 56 metros

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8•7 = 56
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6 0
3 years ago
Find the surface area of a pyramid that is 5 by 7
OLga [1]
The answer is 35 so that's it
4 0
3 years ago
Boris choos three diffrent numbers.the sum of the three numbers is 36.One of trh numbers is a cube number.the other two number a
inna [77]

Answer:

4,5,27

Problem:

Boris chose three different numbers.

The sum of the three numbers is 36.

One of the numbers is a perfect cube.

The other two numbers are factors of 20.

Step-by-step explanation:

Let's pretend those numbers are:

a,b, \text{ and } c.

We are given the sum is 36: a+b+c=36.

One of our numbers is a perfect cube. a=n^3 where n is an integer.

The other two numbers are factors of 20. bk=20 and ci=20 where a,c,i, \text{ and } k \text{ are integers}.

n^3+\frac{20}{k}+\frac{20}{i}=36

From here I would just try to find numbers that satisfy the conditions using trial and error.

3^3+\frac{20}{2}+\frac{20}{2}

27+10+10

47

3^3+\frac{20}{4}+\frac{20}{5}

27+5+4

36

So I have found a triple that works:

27,5,4

The numbers in ascending order is:

4,5,27

4 0
3 years ago
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