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Rufina [12.5K]
3 years ago
5

The side-by-side boxplots show the ages of all Oscar winners for Best Actress (females) and Best Actor (males). What percentage

of Best Actress winners (among females) lie between Q1 = 28 and Q3 = 41?
    
  A. 25%
  B. 12%
  C. 50%
  D. 75%

Mathematics
1 answer:
Minchanka [31]3 years ago
3 0

The first quartile Q1 shows a partition of the first 25% of the data. In the same way the quartile Q3 shows a partition of 75% of the data.

Then, the difference Q3-Q1, also called the interquartile range shows the central 50% of the data.

Therefore the answer is option C:

The percentage of Best Actress winners (among women) between Q1 = 28 and Q3 = 41 is 50%.

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please help!!! the study conducted was 6 days long: there was 72mm of plant food and it decreased an equal amount each day.
Anuta_ua [19.1K]

Answer:

f(x) = 72 - 12x

Step-by-step explanation:

No. of days of study = 6

Amount of food to use for the 6 days = 72 mm

Given that equal amount of food was used each day, amount used per day = \frac{72}{6} = 12 mm

This would enable us derive a function for the amount of food remaining f(x), which can be expressed as a function of the number of days that have passed, (x).

Thus, we would have:

f(x) = 72 - 12x

Let's check if this equation expresses the relation of the function well.

At the end of day 1, if we used, 12mm, we would have 72 - 12 = 60mm of food remaining.

If we replace x in the equation we derived, we would get the same 60mm as the amount of food remaining.

If you try 2, 3, 4, 5 days, you'd get same thing.

At the end of the study, after the 6th day, the food would remain nothing.

Replace 6 for x in the relation function derived, you'd get a value of 0.

6 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
Find the distance between G(-8,6) and H(5, 10). Round to the nearest tenth (one decimal place) if necessary.
Darya [45]

Answer:

1273888364 jsjsjsj difundió doctorado doctor

3 0
3 years ago
Find the value of cos 28°​cos 62°​– sin 28°​sin 62°​
Romashka [77]
<h2>Answer:</h2>

cos 28°​cos 62°​– sin 28°​sin 62°​ = 0

<h2>Step-by-step explanation:</h2>

From one of the trigonometric identities stated as follows;

<em>cos(A+B) = cosAcosB - sinAsinB             -----------------(i)</em>

We can apply such identity to solve the given expression.

<em>Given:</em>

cos 28°​cos 62°​– sin 28°​sin 62°​

<em>Comparing the given expression with the right hand side of equation (i), we see that;</em>

A = 28°

B = 62°

<em>∴ Substitute these values into equation (i) to have;</em>

<em>⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°</em>

<em />

<em>Solve the left hand side.</em>

<em>⇒ cos(90°) = cos28°cos62° - sin28°sin62°</em>

⇒ 0 = <em>cos28°cos62° - sin28°sin62°     (since cos 90° = 0)</em>

<em />

<em>Therefore, </em>

<em>cos28°cos62° - sin28°sin62° = 0</em>

<em />

<em />

8 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
puteri [66]

Answer:

22.5

Step-by-step explanation:

You just have to do 60 divided by 2.66   (The decimal form of 2/3) and then you have your answer PLEASE BRAINLIEST

5 0
3 years ago
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