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Flura [38]
2 years ago
11

Which best models a plane?1)a floor2)a pebble3)a jump rope4)a stick ​

Mathematics
2 answers:
masya89 [10]2 years ago
8 0

Step-by-step explanation:

1) A floor

nikdorinn [45]2 years ago
4 0

Maybe 3, a jump rope. Because the faster you spin the jump rope (propellers), the higher you have to jump (fly)

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Find the midpoint of each line segment
devlian [24]

Answer:

(\frac{7}{2},\frac{1}{2})

Step-by-step explanation:

For this you use the midpoint formula

(\frac{x_{2} +x_{1} }{2} ,\frac{y_{2} +y_{1} }{2} )

the points would be (2,1) and (5,2)

The midpoint would be (\frac{7}{2},\frac{1}{2})

5 0
2 years ago
What is the slope of the line?
Vsevolod [243]

Answer:

2

Step-by-step explanation:

Slope (m) is equal to the change in the y-coordinate divided by the change in the x-coordinate.

The change in y= 6

The change in x= 3

6/3 =2

5 0
2 years ago
Read 2 more answers
pls help.... Natalie plans to run 5 miles every week for 3 weeks. The first day of the first week she ran 1 1/5 miles. How mant
yarga [219]

Answer:

3 4/5

Step-by-step explanation:

If Natalie runs 5 miles each week and she already ran 1 1/5 then she will need to run 3 4/5.

5 - 1 1/5 = 3 4/5

7 0
1 year ago
Find the values of X and Y
frutty [35]

Answer:

y is equal to 2 and x is equal to 31 degrees.

Step-by-step explanation:

In order to find this, we must note that similar parts of congruent triangles are congruent. Since y is congruent to the part that is labeled 2, then it is an easy comparison.

x is a bit trickier. For this one, we must find the missing angle of the first triangle. To get that, we must subtract the given angle and the right angle from 180. This will give us x.

180 - 59 - 90 = x

31 = x

8 0
3 years ago
Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
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