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3 years ago

14

Write the correct answer:

1 answer:

natta225 [31]3 years ago

8 0

Answer:

-1 for question 1, -11 for question 2, 7 for question 3

Step-by-step explanation:

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$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$450\\
P=\textit{original amount deposited}\to& \$3000\\
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\end{cases}
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Exercise 1.A committee of five people is chosen randomly from four men and six women. Find the probability that:a) Exactly four

MatroZZZ [7]

Answer with explanation:

Given : Number of men = 4

Number of women = 6

Total people = $6+4=10$

Total number of ways to make a committee of five people from 10 persons :-

$^{10}C_{4}=\dfrac{10!}{4!(10-4)!}=210$

a) Number of ways to make committee that has exactly four women :

$^6C_4\times ^4C_1=\dfrac{6!}{4!(6-4)!}\times4=60$

The probability that committee has exactly four women :

$\dfrac{60}{210}=\dfrac{2}{7}$

b) Number of ways to make committee that has at-least four women :

$^6C_4\times ^4C_1+^6C_5=\dfrac{6!}{4!(6-4)!}\times4+6=66$

The probability that committee at-least four women :

$\dfrac{66}{210}=\dfrac{22}{70}$

c) Number of ways that committee has more than 4 women :-

$^6C_5\times^4C_0=6$

The probability that committee has more than 4 women :-

$\dfrac{6}{210}$

Now, the probability that committee has at most four women :-

$1-\dfrac{6}{210}=\dfrac{204}{210}=\dfrac{102}{105}$

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