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Hoochie [10]
3 years ago
14

Write the correct answer:

Mathematics
1 answer:
natta225 [31]3 years ago
8 0

Answer:

-1 for question 1, -11 for question 2, 7 for question 3

Step-by-step explanation:

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A distribution x is known to have a mean value of 5 and a standard deviation of 5. what is its mean square value (i.e., the expe
telo118 [61]
\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2
\implies 5^2=\mathbb E(X^2)-5^2
\implies\mathbb E(X^2)=50
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3 years ago
What heat transfer is Christmas lights radiation or convention or conduction
Firdavs [7]

Answer:

The heat from the sun or heat released from the filament of a light bulb is the example of radiation.

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Help me please i reallly need it​
xxMikexx [17]

Answer:

a) A = 64(2s - 1)

b) A = 1,856 cm²

Step-by-step explanation:

Given the side of the frame, 8s, and that the border that frames the picture is 4 on either side = 8:

<h3>a) Find an expression for the area of the frame, in factored form. </h3>

A = area of the square frame

A₁ = Total area (including the picture inside the frame) = (8s)²

A₂ = Area of the picture inside the frame = 4 + 4 = (8s - 8)²

To find the area of the frame, subtract the area of the picture from the total area.

A = A₁ - A₂

A = (8s)² - (8s - 8)²

Perform the necessary exponential operations:

A = 64s²- (64s² - 64s - 64s + 64)

A = 64s²- (64s² - 128s + 64)

A = 64s²- (64s² - 128s + 64)

Distribute -1 into the parenthesis:

A = 64s²- 64s² + 128s - 64

Combine like terms:

A = 0 + 128s - 64

A = 128s - 64

Factor out 64:

A = 64(2s - 1)

The expression for the area of the frame in factored form is: A = 64(2s - 1).

<h3>b) Determine the area of the frame when s = 15cm</h3>

Using the same expression from part A:

A = 64(2s - 1)

Substitute s = 15 into the expression:

A = 64[2(15) - 1]

A = 64(30 - 1)

A = 64(29)

A = 1,856 cm²

Therefore, the area of the frame that has a side of 15 cm is: A = 1,856 cm²

6 0
3 years ago
How can I use the figure to find the exact value of sin 2theta?
Iteru [2.4K]

Answer:

sin(2θ) = 24/25

Explanation:

In order to find the value of sin 2θ, first, recall the double-angle formula for sine.

\sin 2\theta=2\sin \theta\cos \theta

From the right-triangle:

\begin{gathered} \sin \theta=\frac{\text{Opposite}}{\text{Hypotenuse}}=\frac{3}{5} \\ \cos \theta=\frac{\text{Adjacent}}{\text{Hypotenuse}}=\frac{4}{5} \end{gathered}

Substitute these values into the double-angle formula obtained earlier.

\begin{gathered} \sin 2\theta=2\sin \theta\cos \theta \\ =2\times\frac{3}{5}\times\frac{4}{5} \\ =\frac{24}{25} \end{gathered}

The exact value of sin(2θ) is 24/25.

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1 year ago
Which description is correct for the polynomial 2x^2 + 2?
julia-pushkina [17]

D. Quadratic Binomial

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