Two inequalities are equivalent if they have the same set of solutions.
x - 5 ≤ 6 - 5
x - 5 ≤ 1 |add 5 to both sides
x ≤ 6
The distributive property: <em>a(b + c) = ab + ac</em>
2(h + 4) + 6(g + 3) + 5h
= (2)(h) + (2)(4) + (6)(g) + (6)(3) + 5h
= 2h + 8 + 6g + 18 + 5h <em>cimbine like terms</em>
= (2h + 5h) + 6g + (8 + 18)
<h3>= 7h + 6g + 26</h3>
Answer:
To write a linear equation in standard form, move each variable term to the left side of the equation and simplify.
A
x
+
B
y
=
C
Since
x
is on the right side of the equation, switch the sides so it is on the left side of the equation.
3
x
−
2
=
y
Move
y
to the left side of the equation because it contains a variable.
3
x
−
2
−
y
=
0
Move
2
to the right side of the equation because it does not contain a variable.
3
x
−
y
=
2
Step-by-step explanation:
I think the answer is r = 5/12
Honestly, this one works out to be a quadratic (which I don't really feel like going into detail) . . . so instead, since this one is fairly simple to think about, I'll simply try "trial and error" . . .
Possible combinations:
1 × 36 = 36
2 × 18 = 36
3 × 12 = 36
4 × 9 = 36
6 × 6 = 36
Obviously, multiply 4 × 2 = 8 . . . and 9 is one more than 8, which is 2 times the first number, 4 . . . so that's your answer . . .
the numbers are 4 and 9
