5x + 3 = 38
5x = 38-3
5x = 35
x= 7
Not possible, you know you have to have at least 5 nickels so substract those first, now your at 4.50. you cant get to 54 coins after that
1. Quadratic equations have the highest degree of 2. Therefore, the maximum amount of solutions can be 2 or unreal. The graphs with 2 solutions would cross over the x-axis twice, 1 solution would touch the x-axis once and 0 solutions would not touch the x-axis.
2. Find x and y intercepts of the equation. Calculate points at a constant intervals and plot points on graphing paper. Connect the points.
3. Following the movement of a ball through air? <-- not sure about this one
Hope I helped :)
Answer:
No solution
Step-by-step explanation:
![-3x-4y-3z=-7\\2x-6y+2z=3\\5x-2y+5z=9\\\\](https://tex.z-dn.net/?f=-3x-4y-3z%3D-7%5C%5C2x-6y%2B2z%3D3%5C%5C5x-2y%2B5z%3D9%5C%5C%5C%5C)
Lets consider the equation 2.
Here we multiply the LHS and RHS with (-1).
![-3x-4y-3z=-7\\-(2x-6y+2z)=-3\\5x-2y+5z=9\\\\](https://tex.z-dn.net/?f=-3x-4y-3z%3D-7%5C%5C-%282x-6y%2B2z%29%3D-3%5C%5C5x-2y%2B5z%3D9%5C%5C%5C%5C)
Hence,
![-3x-4y-3z=-7\\-2x+6y-2z=-3\\5x-2y+5z=9\\\\](https://tex.z-dn.net/?f=-3x-4y-3z%3D-7%5C%5C-2x%2B6y-2z%3D-3%5C%5C5x-2y%2B5z%3D9%5C%5C%5C%5C)
When we add the equations we get,
![0x+0y+0z=-10+9\\Hence,\\0=-1](https://tex.z-dn.net/?f=0x%2B0y%2B0z%3D-10%2B9%5C%5CHence%2C%5C%5C0%3D-1)
As 0 doesn't equal to -1, answer is d) No solution