The general equation of the circle is:

(x -xo)^2 + (y - yo)^2 = r^2

Where xo,yo are the coordinates of the center and r is the radius of the circle.

Here (xo,yo) is (-16,30) and you can find the radius.

You can find the radius using the equation of the distance (Pythagoras) between the center (-16,30) and any point on the circunference. Here use (0,0)

r^2 = (-16 - 0)^2 + (30 - 0)^2 = 1156

Then, the equation is>

(x - (-16) )^2 + (y - 30)^2 = 1156

=> (x + 16)^2 + (y - 30)^2 = 1156. <----- answer

4 0

3 years ago

Find the area of the circle below:<br> 4 in<br> Round to the nearest TENTHS place.

yawa3891 [41]

Answer:

12.56 =13

Step-by-step explanation:

Area of Circle is =

$\pi \: r ^{2}$

R=2 in

Putting value of r in formula.

Area of Circle =12.56=13

Please mark branliest if you satisfied with the answer. Thanking you in anticipation.

8 0

3 years ago

Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3?

Vilka [71]

Answer:

Option 2: $y - 2 = \frac{1}{3}(x-3)$ is the correct answer.

Step-by-step explanation:

The equation of a line with given point(x1,y1) and slope m is given by:

$y-y_1 = m(x-x_1)$

The line passes through (x1,y1)

Given

$(x_1,y_1) = (3,2)\\m = \frac{1}{3}$

=> x1 = 3

=> y1 = 2

Putting the values of x1, y1 and slope(m) in the point-slope form, the equation of line is:

$y - 2 = \frac{1}{3}(x-3)$

Hence,

Option 2: $y - 2 = \frac{1}{3}(x-3)$ is the correct answer.

3 0

3 years ago

Please help me with this question

kramer

I think it's B The correct answer is B

5 0

3 years ago