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3 years ago

Find the slope for the following coordinates: (3, -7) and (6, 5)

1 answer:

6 0

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{3}}}\implies \cfrac{5+7}{3}\implies \cfrac{12}{3}\implies 4$

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Free_Kalibri [48]

Answer:

5692.421

Step-by-step explanation:

3.421 + 5689 = 5692.421

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3 years ago

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tiny-mole [99]

3x <span>≥ 20

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3 years ago

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+121t

Alenkasestr [34]

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

$h(t)=-4.9t^2+121t+283$

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

$h(t)=0\implies-4.9t^2+121t+283=0$

Using the quadratic formula, the solution for our problem is

$\begin{gathered} t=\frac{-(121)\pm\sqrt{(121)^2-4(-4.9)(283)}}{2(-4.9)} \\ =\frac{121\pm142.083778...}{9.8} \\ =\frac{121+142.083778...}{9.8} \\ =26.8452834694... \end{gathered}$

The rocket splashes after 26.845 seconds.

The maximum of this function happens at the root of the derivative. Differentiating our function, we have

$h^{\prime}(t)=-9.8t+121$

The root is

$-9.8t+121=0\implies t=\frac{121}{9.8}=12.347$

Then, the maximum height is

$h(12.347)=1029.99$

1029.99 meters above sea level.

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1 year ago

Which of the following is equivalent to (n-3)(n-5) a. n2-8n+15, b. n2+8n-15, c. n2-15n+8

solong [7]

Foil the binomials

First: n*n=n^2
Outer: n*-5=-5n
Inner: -3*n=-3n
Last: -3*-5=15

Put it together and simplify
n^2-5n-3n+15
n^2-8n+15

Final answer: A

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3 years ago

The length of one leg of a right triangle is 9cm and 40cm

Damm [24]

Answer:

Step-by-step explanation:

I think ur is D but I'm not sure

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