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3 years ago

PLSSSSSS help ASAP ANSWER 3 OF THEM PLSS

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

9. x=2

10. x=-7

11. x=5

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I need help with this question.

ahrayia [7]

Answer:

Step-by-step explanation:

We know that all the angles must add up to 180

so we have

38+2b-20+b-15=180

solve for b

3b+3=180

3b=177

b=59

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2 years ago

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If f(x) = integral of 1/ (sqrt of t^3 +2)dt, then f'1 = ?

mihalych1998 [28]

Differentiating an integral removes the integral.

f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.

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3 years ago

Elliot and Katy both bought the same lunchbox for $6. Elliot lives in Oklahoma and pays 4.5% in sales tax, while Katy lives in S

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The answer is <span>A.$0.09!

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3 years ago

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Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
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3 years ago

0.5 gallons plus 0.5 gallons plus 2 gallons plus 1gallon basicly i need to know how to add gallons.

gulaghasi [49]

Answer: 5 gallons

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