Answer:
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
And the 90% confidence interval would be given (0.131;0.169).
Step-by-step explanation:
We have the following info given:
represent the sampel size slected
number of students who read above the eighth grade level
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
The confidence interval for the proportion would be given by this formula
For the 90% confidence interval the significance is 
and 
, with that value we can find the quantile required for the interval in the normal standard distribution and we got.
And replacing into the confidence interval formula we got:
And the 90% confidence interval would be given (0.131;0.169).
If the legs are length a and b and hyptonuse is c then
a²+b²=c²
so
if the legs are 20 and 21 and the hypotnuse is x then
20²+21²=x²
400+441=x²
841=x²
29=x
Answer:
just look it up on the internet and it will have brainly and you click on the one that says brainly an you will have the answer
Answer:
20π square units
Step-by-step explanation:
The sector area is found using the proportion ...
sector area / circle area = sector angle / whole circle angle
Multiplying by "circle area", we get ...
sector area = (circle area)( sector angle / whole circle angle)
= (100π)(2/5π)/(2π)
= (100π)(1/5)
sector area = 20π
