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Sophie [7]
3 years ago
9

The school principal wants to order 2 pencils for the 425 students in the school. How many boxes should she order?

Mathematics
2 answers:
sleet_krkn [62]3 years ago
7 0
B because 425 students needs pencils for math work
olganol [36]3 years ago
5 0
How many pencils are in each box
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Pleaseer❤️❤️ help me
defon

Answer:

1)D 2)C 3)A 4)B 5) A

Step-by-step explanation:

1) The area rectangle is 36x^2 -1

We know ,

A= l*b

=36x^2 -1

=(6x)^2 -1

=(6x+1) (6x-2)

This the value of l,b respectively.

So, Perimeter of rectangle is 2(l+b)

P=2(6x+1) + 2(6x-1)

=24x

2)The area of square is 4(x+5)^2

We know,

A=l^2

=4(x+5)^2

=4(x^2 + 10x + 25)

=(2x+10)^2

This is the value of l=2x+10.

So, Perimeter of square is 4l

P=4(2x+10)

=8x+40

3)The fully factorized form is

= -2x^2 + 10x +12

= -2x^2 + 12x -2x +12

= -2x(x-6) -2(x-6)

= -2(x-6) (x+1)

4)The fully factorized form is

=x^4 -81

=(x^2)^2 -9^2

=(x^2 + 9) (x^2 - 9)

=(x^2 + 9) (x^2 - 3^2)

=(x^2 + 9) (x + 3) (x - 3)

5)The fully factorized form is

= 5x^4 - 320

= 5(x^4 - 64)

= 5((x^2)^2 - 8^2)

= 5(x^2 + 8) (x^2-8)

8 0
4 years ago
Is Janelle correct? Yes, because the lines are not parallel. Yes, because the lines will intersect. No, because the lines are in
Over [174]

Answer:

Step-by-step explanation:

No, because the lines are in the same plane.

8 0
3 years ago
can someone help me, Just the answer don’t worry about explaining everything, Im really bad on Math :(
Strike441 [17]

Answer:

a. -2 b. -2 c. -1 d. 4 e. -3 f. 0

Step-by-step explanation:

The average rate of change formula is:

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}

a.  

We need to find the rate of change for x = -3 to x = -2 so we look on the graph to find y.

At x = -3 it look like y = 0  so

x_{1} = -3

y_{1} = 0

At x = -2 it looks like y = 2

x_{2} = -2

y_{2} = 2

Now we can just plug everything in to the rate of change formula.

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{2- 0}{-3-(-2)} = \frac{2- 0}{-3+2} = \frac{2}{-1} = -2

So for a. our rate of chage for the given interval is -2

b.

Now that you have the formula we don't need to explain each time.

x_{1} = -2

y_{1} = 2

x_{2} = 1

y_{2} = - 4

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-4- 2}{1-(-2)} = \frac{-4-2}{1+2} = \frac{-6}{3} = -2

c.

x_{1} = 0

y_{1} = -3

x_{2} = 1

y_{2} = - 4

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-4-(-3)}{1-0} = \frac{-4 + 3}{1-0} = \frac{-1}{1} = -1

d.

x_{1} = 1

y_{1} = -4

x_{2} = 2

y_{2} = 0

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{0 - (-4)}{2-1} = \frac{0 + 4}{2-1} = \frac{4}{1} = 4

e.

x_{1} = -1

y_{1} = 0

x_{2} = 0

y_{2} = -3

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-3- 0}{0-(-1)} = \frac{-3- 0}{0+1} = \frac{-3}{1} = -3

f.

x_{1} = -1

y_{1} = 0

x_{2} = 2

y_{2} = 0

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{0- 0}{2-(-1)} = \frac{0- 0}{2+1} = \frac{0}{3} = 0

4 0
3 years ago
Y=3x+5<br> y=-2x+20<br><br> what does y=
vichka [17]

Answer:

y=14

Step-by-step explanation:

8 0
3 years ago
Can you please help me with these ratios?
Arturiano [62]

Okay, so, for Problem number 1, we see that 30:36 and then we have 5:? Well, to get the five, we divided by 6. So that means we have to do the same thing to the 36 to make the ratios equivalent (equal to) each other. Final Answer: 6

For number 2, it’s a little different. We have what our ratio is equal to, but not the entire starting ratio. However, if we look we see that we have a 6 in the first part and a 3 in the second. That must mean that we divided the 6 by 2 to get the 3. 8 divided by 2 is equal to 4, so our final answer would be 8.

In number 3, we multiplied by 2, because 2x2=4. So we would multiply the 1 by 2 to get that blank space. Final Answer: 2

For number 4, we multiplied by 5. Now we just have to multiply 2 by 5 to get the answer, which is 10.

Lastly on number 5, we are multiplying by 2. To find the blank space, we have to do the “invers operation” which is the opposite operation. So instead of multiplication, we’ll use division. We are going to divide 18 by 2 to get the blank spot. Final answer: 9


6 0
3 years ago
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