What is the sine of C if triangle ABC has b = 3, c = 7, and angle B = 15°?
2 answers:
Answer:
sin C = 0.6039111053
Step-by-step explanation:
The Law of sine can be used to solve this question. Sine formula for triangle can be represented using the picture of the triangle above.
a/sin A = b/sin B = c/sin C
b = 3
c = 7
B = 15°
Inputting the value in the equation
b/sin B = c/sin C
3/sin 15 = 7/sin C
cross multiply
3 sin C = 7 sin 15°
3 sin C = 7 × 0.2588190451
3 sin C = 1.811733316
sin C = 1.811733316/3
sin C = 0.6039111053
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Answer:
or
Step-by-step explanation:
Given:
A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gives 7 peaches to a 5th person.
Remaining peaches = 4
We need to find the original number of peaches in the basket.
The farmer gives the total number of peaches =
Let x be the former gives the total number of peaches
We multiply and divide by 120 in right side of the above equation because of 120 is divided by all given denominator and then simplify.
We add the remaining peaches by given peaches for the original number of peaches in the basket.
Original number of peaches =
Original number of peaches =
Original number of peaches =
Original number of peaches =
Original number of peaches =
Therefore the original number of peaches in the basket is or