Answer:
x= -1/4
Step-by-step explanation:
suppose ,
The number is x
now,
twice a number = 2 . x = 2x
The product of twice a number and six = 2x . 6 = 12x
[ "product" means the result of multiplication]
Then,
Eleven times the number = 11 . x = 11x
The difference of eleven times the number and 1/4 = 11x - 1/4
= (44x-1)/4
Hence,
12x = (44x-1)/4
=>48x = 44x-1 [multiplied by 4 on both sides]
=>48x-44x=-1 [subtract 44x on both sides]
=>4x=-1 [divide both sides by 4]
=>x= -1/4
Answer:
i dont know
Step-by-step explanation:
hynmk,likujnyhbgfd
0.95c
100% minus 5% is 95%, or 0.95. This means Sally only has to pay 0.95 times the grocery bill, or c, which represents 0.95c.
<h2><em>each student requires 9m² of floor </em></h2><h2><em>and given the no. of students is 50
</em></h2><h2><em>So the total area of the room is 9m²X50=450m²
</em></h2><h2><em>Given the length of the room is 25m
</em></h2><h2><em>so the Breadth is =450/25=18m
</em></h2><h2><em>
</em></h2><h2><em>each student requires 108m³ of space </em></h2><h2><em>so total volume of the room is 108X50=5400m³
</em></h2><h2><em>we know that : Volume=Area X h
</em></h2><h2><em> so⇒5400=450Xh
</em></h2><h2><em> ⇒h=5400/450= 12m</em></h2><h2><em /></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>
Answer:
The probability that a household has at least one of these appliances is 0.95
Step-by-step explanation:
Percentage of households having radios P(R) = 75% = 0.75
Percentage of households having electric irons P(I) = 65% = 0.65
Percentage of households having electric toasters P(T) = 55% = 0.55
Percentage of household having iron and radio P(I∩R) = 50% = 0.5
Percentage of household having radios and toasters P(R∩T) = 40% = 0.40
Percentage of household having iron and toasters P(I∩T) = 30% = 0.30
Percentage of household having all three P(I∩R∩T) = 20% = 0.20
Probability of households having at least one of the appliance can be calculated using the rule:
P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)
P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20 P(at least one of the three) = 0.95
The probability that a household has at least one of these appliances is 0.95
