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Dvinal [7]
3 years ago
6

Can anyone fill in the space please

Computers and Technology
1 answer:
Anton [14]3 years ago
8 0
The answer is the stove which has and pressure
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***PLEASE HELP*** (25 POINTS) Graded Assignment
Leona [35]
When does this have to be done?
8 0
4 years ago
Premise: Tracy has a file that contains a list of actors and the movies in which they acted. She wants to know the top 3 ranked
anzhelika [568]

Answer:

see explaination

Explanation:

Python version : 2.7

Python program to read an input file with specified number of records to read

and output the top 3 ranked actors

The format of input file:

<number of records to read>

<actor_name>,<movie_name>

<actor_name>,<movie_name>

....

'''

#define the file name

filename = 'actors_movies.txt'

# create an empty dictionary to contain the actor name as key and number of movies they have acted as value

actors_movie_count = {}

# open the flie

fp = open(filename)

line = fp.readline() # read the first line

count = int(line)

i = 0

# loop to read count number of lines from file

while i < count:

line = fp.readline() # read a line

data = line.split(",") # split the input data into list of strings using comma as the delimiter

# check if actor name is present in the dictionary, then add 1 to its value

# strip is used to remove any leading or trailing space

if data[0].strip() in actors_movie_count:

actors_movie_count[data[0].strip()] += 1

else: # else insert a new record with actor name as its key and 1 as value

actors_movie_count[data[0].strip()] = 1

i += 1

# close the file

fp.close()

# get the list of names of actors and list of number of movies they have acted

actors = actors_movie_count.keys()

num_movies = actors_movie_count.values()

# loop to sort the actors list and num_movies list in descending order of count of movies

for i in range(len(num_movies)-1):

max = i

for j in range(i+1,len(num_movies)):

if num_movies[j] > num_movies[max]:

max = j

if max != i:

actors[max], actors[i] = actors[i], actors[max]

num_movies[max], num_movies[i] = num_movies[i], num_movies[max]

# rank the actors to add top 3 ranked actors to rank_actors list

rank = 1

rank_actors = []

# add the first actor to list

rank_actors.append(actors[0])

# loop from second to end of actors list

for i in range(1,len(actors)):

# if this actor has same number of movies as the actor before him, then assign same rank

if num_movies[i] == num_movies[i-1]:

# if rank <= 3, add the actor in rank_actors list

if rank <= 3:

rank_actors.append(actors[i])

else: # rank > 3, exit the loop

break

else: # assign 1 more rank that the previous

rank += 1

# if rank <= 3, add the actor in rank_actors list

if rank <= 3:

rank_actors.append(actors[i])

else: # rank > 3, exit the loop

break

# loop to display the top 3 ranked actors

for actor in rank_actors:

print(actor)

#end of program

see attachment for the program screenshot and output

5 0
3 years ago
Stopping, standing, or parking is prohibited _____________.
DENIUS [597]
B within an intersection or on a crosswalk
8 0
3 years ago
8.
mario62 [17]

Answer:

<em>Lillipop</em>

Explanation:

If you have your hands correctly placed on the keyboard, the only hand needed to type the word, "lillipop", is the left hand!

<em>Hope I was of Assistance</em><u><em> #SpreadTheLove <3</em></u>

5 0
3 years ago
Which option describes a balanced slide?
Umnica [9.8K]

Answer: a slide with a size 18 font and five images

Explanation:

the text isnt that big to overpower the images and vise versa

4 0
3 years ago
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