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3 years ago

Please answer this (question on image enclosed)

Mathematics

1 answer:

Anit [1.1K]3 years ago

5 0

Answer:

its 900

Step-by-step explanation:

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The spinner for a board game has eight colors the arrow can land on. What are the degrees of freedom for a goodness-of-fit test

Juliette [100K]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

Number of colors that the arrow can land on = 8

We need to find the degrees of freedom for a goodness of fit test of the fairness of this spinner.

As we know that degree of freedom is 1 less than the size of sample.

So, Mathematically, it is expressed as below:

So, Degree of freedom would be

$v=n-1\\\\v=8-1\\\\v=7$

Hence, Option 'c' is correct.

7 0

3 years ago

Solve irrational equation pls

rusak2 [61]

$\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)$

$
\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\$
$
4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\$

There's one more condition I forgot about
$-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\$

Finally
$x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}$

3 0

3 years ago

Plzzz help me im having alot of trouble understanding this question does some one understand if you do plz help fast!!!

juin [17]

Answer:

1/2 - 3(1/2 + 1)²

simplify the expression (1/2 + 1)

1/2 - 3•(3/2)²

using PEMDAS, we see we have to evaluate the exponent first

(3/2)² = 9/4

rewrite the equation

1/2 - 3 • (9/4)

multiply 3 by (9/4)

1/2 - (27/4)

subtract

-25/4

(1 + 1/3)² - 2/9

simplify the expression (1 + 1/3)

(4/3)² - 2/9

using PEMDAS, we see we have to evaluate the exponent first

(4/3)² = 16/9

rewrite the equation

(16/9) - (2/9)

subtract

14/9

5 0

3 years ago

Write 83 as a sum of tens and ones

Travka [436]

8 tens and 3 ones.

hope that helped

6 0

3 years ago

Read 2 more answers

james pays $120.00 for golf clubs that are on sale for 20% off at golf pros. at nine iron the sabe clubs cost $8.00 less than th

Alexandra [31]

The answer is 126.56 really hope that’s right:)

3 0

3 years ago