A and D, sorry if I’m wrong.
Q(3) = -2(3)+2 = -4
r(q(3)) = (-4)^2-1 = 15
Answer:
f(x inv)=-1/2x-3
Step-by-step explanation:
You pretty much just have to flip all the numbers to fractions and all the positives to negatives.
Answer:
44%
Step-by-step explanation:
you add up all the numbers to get the total then divied the single number (eg. 8) by the total. It will then show up as a decimal so in order to get rid of the decimal you multiply by 100. ( eg. 8 ÷50=0.16 → 0.16×100= 16 → 16% )
Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper =
sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining = 
= 
Using algebraic formula: 

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.