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3 years ago

How do you determine if a given set of measurements works for the side lengths of a triangle? (It should be a number)

Mathematics

1 answer:

zaharov [31]3 years ago

5 0

Add them all up and if they add up to 180 then your side lengths are good

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What is the slope intercept form of the equation 4x-8y=72

Masteriza [31]

Answer:

y = 1/2x - 9

General Formulas and Concepts:

Alg I

Standard Form: Ax + By = C

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

Step 1: Define

Standard Form: 4x - 8y = 72

Step 2: Find slope-intercept form

Subtract 4x on both sides: -8y = 72 - 4x
Divide both sides by -8: y = -9 + 1/2x
Rewrite: y = 1/2x - 9

6 0

3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

Consider the box plot.

Anna [14]

Answer:

Step-by-step explanation:

The box plot explains the right numbers in order

8 0

2 years ago

SOMEONE PLEASE HELP ME

notka56 [123]

Area of deck= 2(20w)+4(w^2)+2(50w)d
456=2(20w)+4(w^2)+2(50w)

456=40w+4w^2+100w

456=4w^2+140w

114=w^2+35w

0=w^2+35w-114

find what 2 numbers multiply to get 114 and add to get 35 and factor

-3 and 38

0=(w-3)(w+38)

set each to zero

w-3=0

w=3

3 0

3 years ago

Help me please yall are basically the best

egoroff_w [7]

Answer:

4 i think

Step-by-step explanation:

6 0

3 years ago