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3 years ago

what would be the equation of a line that passes through (3,-4) with slope 2/3

Mathematics

1 answer:

Len [333]3 years ago

7 0

Answer:

y = 2/3x - 6

Step-by-step explanation:

Use the slope intercept equation, y = mx + b

Plug in the slope and given point, then solve for b

y = mx + b

-4 = 2/3(3) + b

-4 = 2 + b

-6 = b

Plug in the slope and b into the equation

y = 2/3x - 6

So, the equation of the line is y = 2/3x - 6

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Michael bought vegetables that weights 4 1/8 pounds. How many ounces does the vegetables weigh?

Naddik [55]

There are 16 ounces in a pound. So in 4 1/8 pounds, there would be 66 ounces.

8 0

3 years ago

Read 2 more answers

The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households

liq [111]

Answer:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b) 2.70

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

b. 1.85

$p_v =P(Z>1.85)=0.032$

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

$\bar X_{1}=164$ represent the mean for the sample 1

$\bar X_{2}=159$ represent the mean for the sample 2

$\sigma_{1}=12.5$ represent the population standard deviation for the sample 1

$s_{2}=9.25$ represent the population standard deviation for the sample B2

$n_{1}=35$ sample size selected 1

$n_{2}=30$ sample size selected 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

$SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}$

Replacing the values that we have we got:

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

P-value

Since is a one side right tailed test the p value would be:

$p_v =P(Z>1.85)=0.032$

b. 0.03

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

4 0

3 years ago

There are 3 types of gummy bears:

mr Goodwill [35]

Using proportions, it is found that it takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

10 mini-bears weights to 12.1 grams, hence the weight of a mini-bear is of:

12.1/10 = 1.21 grams.

10 regular bears weights to 23.1 grams, hence the weight of a regular bear is of:

23.1/10 = 2.31 grams.

1 super bear weights to 2250 grams, hence the proportion between the <u>weight of a super bear and the weight of a mini-bear</u> is:

2250/1.21 = 1860.

The proportion between the <u>weight of a super bear and the weight of a regular bear</u> is:

2250/2.31 = 974.

The difference of proportions is given by:

1860 - 974 = 886.

It takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

5 0

11 months ago

At the gym, Jasper was able to bench press 224 pounds, which was 7/8 of the weight that Balin was able to bench press. Which sho

Rzqust [24]

Answer:

The answer SHOULD be 7/8=224/x;256 pounds.

You may have made a mistake in inputting it here on Brainly. So look for the one that matches that.

Step-by-step explanation:

This is what we know:

Jasper = 224 pounds

Balin = x

Jasper = 7/8 of x

Now we make an equation for that:

$(\dfrac{7}{8})(x) = 224pounds$

To match the selections we will isolate 7/8 on one side of the equation:

$\dfrac{7}{8}=\dfrac{224}{x}$

Using ratio and proportion we can solve for what x is. Multiply 224 by 8 and divide it by 7. Or you can do it this way too:

$\dfrac{7}{8}=\dfrac{224}{x}$

$(7)(x)=(224pounds)(8)$

$7x=1792pounds$

$x=\dfrac{1792pounds}{7}=256pounds$

So x = 256 pounds

7 0

3 years ago

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Michael earns $8 an hour to baby sit the Jackson family. How many hours does he have to 1 point

notsponge [240]

Answer:

7 hours

Step-by-step explanation:

56/8=7

7 0

3 years ago

￼ ￼what would be the equation of a line that passes through (3,-4) with slope 2/3

what would be the equation of a line that passes through (3,-4) with slope 2/3