Replace x with π/2 - x to get the equivalent integral
but the integrand is even, so this is really just
Substitute x = 1/2 arccot(u/2), which transforms the integral to
There are lots of ways to compute this. What I did was to consider the complex contour integral
where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be
which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit
and it follows that
I think that is correct !!
Answer:
0.970873786408%
Step-by-step explanation:
calculator
Answer:
4.66 (4 2/3, 14/3)
Step-by-step explanation:
9514 1404 393
Answer:
97.42 square units
Step-by-step explanation:
The area of a sector is given by ...
A = (1/2)r²θ
where r is the radius (12.2) and θ is the central angle in radians. Here, you're given the central angle as 75°, so you need to convert that to radians.
75° = (75°)×(π/180°) radians = (5/12)π radians
Then the area is ...
A = (1/2)(12.2²)(5π/12) = 744.2π/24 ≈ 97.42 . . . square units
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Equivalently, you can find the area of the circle in the usual way:
A = πr² = π(12.2²) ≈ 467.59465
Then, multiply by the fraction of the circle that is shaded (75°/360°)
sector area = (467.59465)(75/360) = 94.42 . . . square units
