Question

at noon a tank contains 10 cm of water after several hours it contains 7 cm of water what is the percent decrease of water in the tank

Answer 1

Answer:

30%.

Step-by-step explanation:

We have been given that at noon a tank contains 10 cm of water after several hours it contains 7 cm of water.

To find the decrease percent we will use formula:

$\text{Decrease percent}=\frac{\text{Original value-new value}}{\text{Original value}}\times 100$

Upon substituting our given values in above formula we will get,

$\text{Decrease percentage of water in the tank}=\frac{10-7}{10}\times 100$

$\text{Decrease percentage of water in the tank}=\frac{3}{10}\times 100$

$\text{Decrease percentage of water in the tank}=3\times 10=30$

Therefore, the percentage decrease of water in the tank is 30%.